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2 years ago

An example of gaining potential energy

Chemistry

1 answer:

aleksandr82 [10.1K]2 years ago

5 0

Answer:

An example for gaining potential energy would be: A glass bottle on the top of a high shelf would have more high potential energy than a glass bottle on the middle or bottom shelf because it has a long way or more farther to fall down or brake.

Explanation:

Remember Potential Energy is the restored energy of an object has.

I hope this helps you!

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How many moles of hypomanganous acid. H3 MnO4, are contained in 22.912 g?

gregori [183]

Answer:

0.188mol

Explanation:

Using the formula;

mole = mass/molar mass

Molar mass of hypomanganous acid. (H3MnO4) = 1(3) + 55 + 16(4)

= 3 + 55 + 64

= 122g/mol

According to this question, there are 22.912g of H3MnO4

mole = 22.912g ÷ 122g/mol

mole = 0.188mol

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3 years ago

Some of the most dangerous conditions occur when temperatures are hovering around _______ degrees fahrenheit, or freezing, when

Olin [163]

Answer:

32 ° F

Explanation:

Freezing temp for water is 32 degrees at 1 atm

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1 year ago

What is heat of vaporization?

kirza4 [7]

B. It is the heat required to change a gram of substance from solid to liquid

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2 years ago

Read 2 more answers

Is lemonade aquoes solution

masha68 [24]

Answer:

contains water...

Explanation:

the solvent is water, so yes.

4 0

3 years ago

A NaOH solution is standardized using the monoprotic primary standard potassium hydrogen phthalate, KHP (204.22 g/mol.) If 0.698

kakasveta [241]

Answer:

0.07789 M is the sodium hydroxide concentration.

Explanation:

Mass of potassium hydrogen phthalate = 0.6986 g

Molar mass of potassium hydrogen phthalate = 204.22 g/mol

Moles of potassium hydrogen phthalate = $\frac{0.6986 g}{204.22 g/mol}=0.003421 mol$

$NaOH+KHP\rightarrow NaKP+H_2O$

According to reaction , 1 mole og KHp reactswith 1 mole of NaOH , then 0.003421 moles of KHp will react with :

$\frac{1}{1}\times 0.003421 mol=0.003421 mol$

Moles of NaOH = 0.003421 mole

Volume of NaOH solution = 43.92 ml = 0.04392 L ( 1 mL = 0.001L)

$Concentration=\frac{Moles}{Volume(L)}$

Concentration of NaOH :

$\frac{0.003421 mol}{0.04392 L}=0.07789 M$

0.07789 M is the sodium hydroxide concentration.

5 0

3 years ago