Answer:
a) The maximum height the ball will achieve above the launch point is 0.2 m.
b) The minimum velocity with which the ball must be launched is 4.43 m/s or 0.174 in/ms.
Explanation:
a)
For the height reached, we use 3rd equation of motion:
2gh = Vf² - Vo²
Here,
Vo = 3.75 m/s
Vf = 0m/s, since ball stops at the highest point
g = -9.8 m/s² (negative sign for upward motion)
h = maximum height reached by ball
therefore, eqn becomes:
2(-9.8m/s²)(h) = (0 m/s)² - (3.75 m/s²)²
<u>h = 0.2 m</u>
b)
To find out the initial speed to reach the hoop at height of 3.5 m, we again use 3rd eqn. of motion with h= 3.5 m - 2.5m = 1 m (taking launch point as reference), and Vo as unknown:
2(-9.8m/s²)(1 m) = (0 m/s)² - (Vo)²
(Vo)² = 19.6 m²/s²
Vo = √19.6 m²/s²
<u>Vo = 4.43 m/s</u>
Vo = (4.43 m/s)(1 s/1000 ms)(39.37 in/1 m)
<u>Vo = 0.174 in/ms</u>
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Answer:
Explanation:
Given that
Stored energy E
a)
We know that stored energy in capacitor given as
Given that
C= 0.02 F
b)
Electric filed E = 9 x 10^6 V/m
We know that
V = E .d
d=1.11 mm
We know that
This is area area of the plates.
Answer:
1 ) Warm air
2) Cold air
3) Cold water
4) Steel
5) Hot molten
Explanation:
In order to solve this problem, we have to warn that the sound propagates more easily in denser media, in this way we have to identify the densities of the different materials.
Density cold air = 1.2 [kg/m^3]
Density warm air = 1.01 [kg/m^3]
Density cold water = 1000 [kg/m^3]
Density steel = 7500 [kg/m^3]
Density hot molten = 14100 [kg/m^3]
Therefore in order from the slowest to the fastest:
1 ) Warm air
2) Cold air
3) Cold water
4) Steel
5) Hot molten
