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Marat540 [252]
3 years ago
13

Planet z has a rocky surface. at height 3240 km above the surface, the gravitational acceleration is what is the radius of the p

lanet?
Physics
1 answer:
jolli1 [7]3 years ago
8 0
Https://www.google.com/search?tbs=sbi:AMhZZiuc6mk5S438WBb7iizj56MvoVz9sxfbOaVcy_1SdDTQnJdcyo0Qu7CKsc...
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A dust particle floats in front of a silent loudspeaker as shown in the figure. The loudspeaker is turned on and plays a constan
dybincka [34]

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tbh idk

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How can we avoid injuries in school or community when engaging in physical activities?
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As you approach your vehicle and perform checks it is not necessary to always
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3 years ago
Army is standing still on the ground; Bill is riding his bicycle at 5 m/s eastward: and Carlos is driving his car at 15 m/s west
Aleks04 [339]

Explanation:

Given that,

Bill is riding his bicycle at 5 m/s eastward: and Carlos is driving his car at 15 m/s westward.

Taking eastward as positive direction, we have:

v_B=+5\ m/sis the velocity of Bill with respect to Amy (which is stationary)

v_c=15\ m/s is the velocity of Carlos with respect to Amy.

Bill is moving 5 m/s eastward compared to Amy at rest, so the velocity of Bill's reference frame is

v_B=+5\ m/s

Therefore, Carlos velocity in Bill's reference frame will be

v_c'=-15\ m/s-(+5\ m/s)\\\\=-20\ m/s

So, the magnitude is 20 m/s and the direction is westward (negative sign).

7 0
3 years ago
A uranium ion and an iron ion are separated by a distance of =61.10 nm. The uranium atom is singly ionized; the iron atom is dou
scoray [572]

Answer:

Explanation:

Charge on uranium ion = charge of a single electron

= 1.6 x 10⁻¹⁹ C

charge on doubly ionised iron atom = charge of 2 electron

= 2 x 1.6 x 10⁻¹⁹ C = 3.2 x 10⁻¹⁹ C

Let the required distance from uranium ion be d .

force on electron at distance d from uranium ion

= 9 x 10⁹ x 1.6 x 10⁻¹⁹ / r²

force on electron at distance 61.10 x 10⁻⁹ - r from iron  ion

= 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²

For equilibrium ,

9 x 10⁹ x 1.6 x 10⁻¹⁹ / r² = 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²

2 d² = (61.10 x 10⁻⁹ - r )²

1.414 r = 61.10 x 10⁻⁹ - r

2.414 r = 61.10 x 10⁻⁹

r = 25.31 nm .

4 0
3 years ago
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