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4 years ago

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Planet z has a rocky surface. at height 3240 km above the surface, the gravitational acceleration is what is the radius of the p

lanet?

1 answer:

jolli1 [7]4 years ago

8 0

Https://www.google.com/search?tbs=sbi:AMhZZiuc6mk5S438WBb7iizj56MvoVz9sxfbOaVcy_1SdDTQnJdcyo0Qu7CKsc...

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A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance

FinnZ [79.3K]

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

6 0

3 years ago

What two important factors determine the nature of an ecosystem?

UNO [17]

The answer is A. a habitat’s features are determined by the abiotic factors such as temperature and humidity.

5 0

3 years ago

Two frisky grasshoppers collide in midair at the top of their respective trajectories and grab onto each other, holding tight th

Svetlanka [38]

Answer:

The decrease in Kinetic energy is 0.0107 Joules

Explanation:

Given

Mass of grasshoppers

Let m1 = Mass of grasshopper 1

Let m2 = Mass of grasshopper 2

Let u1 = initial speed of grasshopper 1

Let u2 = initial speed of grasshopper 2

m1 = 250g = 0.25kg

m2 = 130g = 0.13kg

u1 = 15cm/s = 0.15m/s

u2 = 65cm/s = 0.65m/s

First, we calculate the final velocity of the grasshoppers after collision using conservation of momentum.

Using

m1u1 + m2u2 = (m1 + m2) * v

Where v = final velocity

By substituton

0.25 * 0.15 + 0.13 * 0.65 = (0.25 + 0.13) * v

0.0375 + 0.0845 = 380v

0.122 = 0.38v

Make v the subject of formula

v = 0.122/0.38

v = 0.321 m/s

Calculating the Kinetic energies before and after impact.

Before collision;

KE = ½m1u1²+ ½m2u2²

KE = ½(m1u1² + m2u2²)

By substituton;

KE = ½(0.25 * 0.15² + 0.13 * 0.65²)

KE = 0.030275J

After collision:

KE = ½(m1+m2)v²

KE = ½(0.25 + 0.13) * 0.321²

KE = 0.01957779 J

Change in kinetic energy = ∆KE

∆KE = 0.030275J - 0.01957779J

∆KE = 0.01069721J

∆KE = 0.0107 J --- Approximately

Hence the decrease in Kinetic energy is 0.0107 Joules

7 0

3 years ago

I need the answers to these questions

dimulka [17.4K]

The guy above looks correct

8 0

3 years ago

The flux through the coils of a solenoid changes from 2.57.10-5 Wb to 9.44.10-5 Wb in 0.0154 s. If 4.08 V of EMF is generated, h

Vinil7 [7]

Hello!

We can use Faraday's Law of Electromagnetic Induction to solve.

$\epsilon = -N \frac{d\Phi_B}{dt}$

ε = Induced emf (4.08 V)
N = Number of loops (?)

$\Phi_B$ = Magnetic Flux (Wb)
t = time (s)

**Note: The negative sign can be disregarded for this situation. The sign simply shows how the induced emf OPPOSES the current.

Now, we know that $\frac{d\Phi_B}{dt}$ is analogous to the change in magnetic flux over change in time, or $\frac{\Delta \Phi_B}{\Delta t}$ , so:
$\epsilon = N \frac{\Delta \Phi_B}{\Delta t}\\\\\epsilon = N \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}$

Rearrange the equation to solve for 'N'.

$N = \frac{\epsilon}{ \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}}$

Plug in the given values to solve.

$N = \frac{4.08}{ \frac{9.44*10^{-5} - 2.57*10^{-5}}{0.0154}} = 914.585 = \boxed{915 \text{ coils}}$

**Rounding up because we cannot have a part of a loop.

4 0

2 years ago