The vertical weight carried by the builder at the rear end is F = 308.1 N
<h3>Calculations and Parameters</h3>
Given that:
The weight is carried up along the plane in rotational equilibrium condition
The torque equilibrium condition can be used to solve
We can note that the torque due to the force of the rear person about the position of the front person = Torque due to the weight of the block about the position of the front person
This would lead to:
F(W*cosθ) = mgsinθ(L/2) + mgcosθ(W/2)
F(1cos20)= 197/2(3.10sin20 + 2 cos 20)
Fcos20= 289.55
F= 308.1N
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Answer:

Explanation:
As we know that the orbital speed of the satellite is given as

also we know that
time period of the revolution is given as

now from above equation we know that


so we will have

now plug in all data in this equation


Answer: 6m
Explanation: 6 is more than 3 and their both being measured by m
The weight changes but the mass will stay the same.