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Marina86 [1]
3 years ago
15

PLZ HELP QUICK!!

Chemistry
1 answer:
MissTica3 years ago
8 0
I have the same question too!!!Dang I thought I would get a answer I just guessed
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Translate the words into formulas, predict the product, & balance the equations. Include states of matter.
Andreyy89
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Hibiscus I
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8 0
3 years ago
What is the weight of a 90kg man standing on the moon, where gmoon = 1.64 m/s2?
Doss [256]

Answer:

The weigth of a 90kg man standing on the moon is <u><em>147.6 N (option C)</em></u>

Explanation:

Weight is called the action exerted by the force of gravity on the body.

The mass (amount of matter that a body contains) of an object will always be the same, regardless of where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The formula that allows you to calculate the weight of any body is:

W = m*g

where:

  • W = weight measured in N.
  • m = mass measured in kg.
  • g = acceleration of gravity measured in m/s². The acceleration of gravity g is the same for all objects that fall due to gravitational attraction, whatever their size or composition. For example, as an approximate value on Earth, g = 9.8 m/s².

In this case,  the mass m has a value of 90 kg and the gravity g has a value of 1.64 m/s², which is the value of the acceleration of gravity of the moon. Then:

W=90 kg* 1.64 m/s²

<u><em>W= 147.6 N</em></u>

Finally, <u><em>the weigth of a 90kg man standing on the moon is 147.6 N (option C)</em></u>

3 0
4 years ago
If the mass is 10g and the volume<br> is 2cm3 what is the density?
SSSSS [86.1K]

Answer:

The density is 5 g/cm3

Explanation:

The density (δ) is the ratio between the mass and the volume of a compound:

δ=m/v= 10 g/2 cm3= 5 g/cm3

3 0
4 years ago
In an aqueous solution of a certain acid with pka = 3.75 the ph is 2.82 . calculate the percent of the acid that is dissociated
Arturiano [62]
Hello! Let me try to answer this :)

Thanks and please correct if there are any mistakes ^ ^

8 0
4 years ago
For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomas
Flauer [41]

Answer:

4.25% is the final concentration of phosphoric acid.

Explanation:

Initial concentration of phosphoric acid = C_1=85\%=0.85

Initial volume of phosphoric acid = V_1=50 mL

Final concentration of phosphoric acid = C_2=?

Final volume of phosphoric acid = V_2=1 L=1000 mL

( 1L = 1000 mL)

C_1V_1=C_2V_2

C_2=\frac{C_1times V_1}{V_2}

=\frac{0.85\times 50 mL}{1000 mL}=0.0425=4.25%

4.25% is the final concentration of phosphoric acid.

4 0
3 years ago
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