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3 years ago

Define "Monosaccharide", "Disaccharide", "Oligosaccharide", "Polysaccharide", and "Glucoconjugate"

Chemistry

1 answer:

avanturin [10]3 years ago

6 0

Explanation:

Monosaccharides are the elementary form of the sugar and most basic units of the carbohydrates. These sugars cannot be further hydrolyzed to form the simpler chemical compounds. The general formula is $C_nH_{2n}O_n$ . Example: Glucose and fructose.

Disaccharide is sugar which is formed when the two monosaccharides are joined by the glycosidic linkage. Disaccharides are soluble in the water. Examples: sucrose and lactose.

Oligosaccharide is the saccharide polymer which contains small number of the monosaccharides. They can have many functions like the cell recognition and the cell binding. Example: glycolipids which have role in immune response.

Polysaccharides are the polymeric carbohydrate molecules which are composed of the long chains of the monosaccharide units that are bound together by the glycosidic linkages which on the hydrolysis give constituent monosaccharides or th eoligosaccharides. Example: Starch.

Glycoconjugates is general classification for the carbohydrates which are covalently linked with the other chemical species such as peptides, proteins, saccharides and lipids. Example: Blood proteins

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3 years ago

Calculate the number of water (H2O) molecules produced from the decomposition of 75.50 grams of Iron (III) hydroxide (Fe(OH)3).

Phantasy [73]

Answer: $6.38\times 10^{23}$ molecules of water are produced.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Fe(OH)_3=\frac{75.50g}{106.8g/mol}=0.707moles$

The balanced chemical reaction is:

$2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O$

According to stoichiometry :

2 moles of $Fe_2O_3$ produce = 3 moles of $H_2O$

Thus 0.707 moles of $Fe_2O_3$ will produce= $\frac{3}{2}\times 0.707=1.06moles$ of $H_2O$

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles.

Thus 1.06 moles of $H_2O$ contains = $\frac{6.023\times 10^{23}}{1}\times 1.06=6.38\times 10^{23}$ molecules

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3 years ago

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igomit [66]

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3 years ago

Read 2 more answers

For which compound does 0.256 mole weigh 12.8 g?

mylen [45]

Number of moles = $\frac{mass (g)}{Molar mass}$
so to calculate molar mass (Molecular weight of compound):
Molecular weight = $\frac{mass (g)}{number of moles}$
= $\frac{12.8 g}{0.256 mole}$ = 50 g / mole
Now we calculate molecular weight of each compound in choices:
a) C₂H₄O = 44
b) CO₂ = 44
c) CH₃Cl = 50.4 ALMOST 50 so this is the correct answer
d) C₂H₆ = 30

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3 years ago