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MaRussiya [10]
3 years ago
12

Can anyone give me notes on double bar graph.​

Mathematics
1 answer:
kogti [31]3 years ago
6 0

Answer:

have one bar be red and the other be blue

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What’s the digit you need to input in the space with the question mark to complete the code for the safe? Here’s a hint to save
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Answer:

4

Step-by-step explanation:

2×2=4

6÷2=3

1×2=2

8÷2=4

3×2=6

?÷2=2

2×2=4

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To save money, you put $200 in your bank account each week. After saving for 4 weeks, you have $1,700 dollars in your account. W
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it is c y−1,700=200(x−4)

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3 years ago
The proper height of a highway guardrail is 27 inches, but 3 inches higher or lower is acceptable. Which inequality represents t
andriy [413]

Answer:

Step-by-step explanation:

27 is the "center" of a range of measurements of the height of the guard rail.  The height could be as much as 30 inches or as little as 24 inches.  The absolute value operator encloses "x - 27," where 27 is the "center."  The acceptable excess or acceptable deficiency is 3 inches.  

So now we can eliminate possible answers B and C, in both cases because 27 is inappropriately greater than 3.

Narrowing down our choices, we have h + 27 and h - 27 inside the absolute value operator.  27 is a positive quantity (height of the guard rail), so the inequality showing +27 as the "center" is correct; that is

D:  |h - 27| ≤ 3 (measurements in inches).

3 0
3 years ago
A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
3 years ago
Complete the table.<br> Feet<br> Inches<br> 1<br> 10<br> 60<br> 42
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