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IceJOKER [234]
2 years ago
13

What occurred when rutherford exposed nitrogen gas to alpha particles?

Chemistry
2 answers:
Masteriza [31]2 years ago
5 0

When Rutherford exposed nitrogen gas to alpha particles, some of the alpha particles were absorbed by the nitrogen nuclei.  

A equation for the alpha particle bombardment is as follows:  

¹⁴₇N+⁴₂He---->¹⁷₈O+¹₁H

So, as it can be seen from the equation that some of the alpha particles are absorbed by nitrogen nuclei.


adoni [48]2 years ago
5 0

The conversion of one element to another had occurred.

Please mark me brainiest.

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What atom has 2 electrons, 6 protons and 7 neutrons
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Carbon atoms with 7 neutrons have an atomic mass of 13 (6 protons + 7 neutrons = 13). These atoms are the isotope called carbon-13.Jul

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Which electromagnetic wave has the longest wavelength?
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<span>from longest wavelength to shortest: radio waves, microwaves, </span>infrared<span>, </span>optical<span>, </span>ultraviolet<span>, X-rays, and gamma-rays</span>
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How many grams of aluminum are required to give a total dislocation length of 3,000 miles (enough to stretch from New York City
Luba_88 [7]

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0.13 g

Explanation:

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5 0
3 years ago
You are given sodium acetate, 1m hcl, nahco3 and na2co3. Determine which of these four you would need and then show calculations
valentina_108 [34]

solution:

the given compounds are sodium acetate, 1M HCL,NaHCO₃ and Na2CO₃

pH of the buffer solution is 4.7

the value of pKa of sodium bicarbonate is 6.37

the value of pKa of acetic acid is 4.7

calculate concentration of acetic acid by using the following forumula

pH=pKa+lag[salt]/[acid]

substitute the pH and Pka values in the formula.

4.7=4.7+log[salt]/[acid]

log[salt]/[acid]=0

thus, the concentration ratio of the salt and acid should be equal to each other.

Thus, concentration of sodium acetate is 0.05M

Concentration of sodium acetate= concentration of acid

= 0.05M

Volume of the buffer solution is 100mL

The buffer solution can be prepared as 0.05M of 50mL sodium acetate will react with 0.05M of 50mL of 0.05M of HCL.

The chemical equation for neutralization of the weak base with strong can be represented as show as

CH₃COONa+HCL-->CH₃COOH+NaCL


5 0
3 years ago
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