Statement three i do believe
The rate of energy radiated by the man is 3.86 x
J/s.
.
The amount of energy radiated by an object majorly depends on the area of its surface and its temperature. The is well explained in the Stefan-Boltzmann's law which states that:
Q(t) = Aeσ![T^{4}](https://tex.z-dn.net/?f=T%5E%7B4%7D)
where: Q is the quantity of heat radiated, A is the surface area of the object, e is the emmisivity of the object, σ is the Stefan-Boltzmann constant and T is the temperature of the object.
To determine the rate of energy radiated by the man in the given question;
= Aeσ
But A = 1.7 m², e = 0.4 and σ = 5.67 x
J/s.
So that;
= 1.7 * 0.4 * 5.67 x
= 3.8556 x
= 3.86 x
J/s. ![m^{2}](https://tex.z-dn.net/?f=m%5E%7B2%7D)
Thus, the rate of energy radiated by the man is 3.86 x
J/s.
.
Learn more on energy radiation of objects by visiting: brainly.com/question/12550129
Transverse waves In transverse waves, particles of the medium vibrate to and from in a direction perpendicular to the direction of energy
Hope this answer helps you
<h2>Answer:</h2>
<u>A) Increase the voltage by adding a bigger battery </u>
<h2>Explanation:</h2>
According to Ohm's law
V = IR
where V is voltage, I is current and R is the resistance. If we write the equation for resistance we would get
R= V / I
Here we can see that Voltage is directly proportional to Resistance so in order to keep the balance if we increase the resistance then we must increase the voltage to keep the current constant.
I think it is -3.99 x 102 j