In what way do pigments act differently from light?
2 answers:
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Answer:
K_{e} = 2.0 J
Explanation:
In this exercise you are asked to calculate the elastic potential energy of a spring
= ½ k x²
where k is the spring constant and x is the displacement from equilibrium position
In this exercise, indicate that the spring constant is k = 100 N/m, the length at rest is x₀ = 20 cm = 0.20 m, up to the position x₁ = 40 cm = 0.40 m, therefore the elongation
Δx = x₁ - x₀
Δx = 0.40 - 0.20
Δx = 0.20 m
let's calculate the elastic potential energy
K_{e} = ½ 100 0.20²
K_{e} = 2.0 J
The object has been moved by 5 m
Explanation:
The work done by a force when moving an object (which is equal to the energy used to move the object) is given by
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
In this problem, we have
W = 35 J is the work done
F = 7.0 N is the magnitude of the force
, assuming the force is applied parallel to the direction of motion of the object
Therefore, we can solve the formula for d to find the displacement of the object:
Learn more about work:
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