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Damm [24]
3 years ago
15

Help me please I don’t understand

Physics
1 answer:
IrinaK [193]3 years ago
3 0
A nuclear power plant.
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At one point in a pipeline, the water's speed is 3.57 m/s and the gauge pressure is 68.7 kPa. Find the gauge pressure at a secon
ArbitrLikvidat [17]

Answer:

The  pressure at point 2 is P_2  = 254.01 kPa

Explanation:

From the question we are told that

   The speed at point 1  is  v_1  =  3.57 \ m/s

   The  gauge pressure at point 1  is  P_1  =  68.7kPa =  68.7*10^{3}\  Pa

    The density of water is  \rho  = 1000 \ kg/m^3

Let the  height at point 1 be  h_1 then the height at point two will be

      h_2  =  h_1  -  18.5

Let the  diameter at point 1 be  d_1 then the diameter at point two will be

      d_2  =  2 * d_1

Now the continuity equation is mathematically represented as  

         A_1 v_1  =  A_2 v_2

Here A_1 , A_2  are the area at point 1 and 2

    Now given that the are is directly proportional to the square of the diameter [i.e A=  \frac{\pi d^2}{4}]

   which can represent as

             A \ \  \alpha \ \  d^2

=>         A = c   d^2

where c is a constant

  so      \frac{A_1}{d_1^2}  =  \frac{A_2}{d_2^2}

=>          \frac{A_1}{d_1^2}  =  \frac{A_2}{4d_1^2}

=>        A_2  =  4 A_1

Now from the continuity equation

        A_1  v_1  =  4 A_1 v_2

=>     v_2  =  \frac{v_1}{4}

=>     v_2  =  \frac{3.57}{4}

       v_2  =  0.893 \  m/s

Generally the Bernoulli equation is mathematically represented as

       P_1 + \frac{1}{2}  \rho v_1^2 +  \rho *  g * h_1  =  P_2 + \frac{1}{2}  \rho v_2^2 +  \rho *  g * h_2

So  

         P_2  =  \rho  * g  (h_1 -h_2 )+P_1  +  \frac{1}{2}  *  \rho (v_1^2 -v_2 ^2 )  

=>    P_2  =  \rho  * g  (h_1 -(h_1 -18.3)  + P_1  +  \frac{1}{2}  *  \rho (v_1^2 -v_2 ^2 )

substituting values

        P_2  =  1000  * 9.8  (18.3) )+ 68.7*10^{3}  +  \frac{1}{2}  *  1000 ((3.57)^2 -0.893 ^2 )

       P_2  = 254.01 kPa

 

8 0
3 years ago
You drop two balls of equal diameter from the same height at the same time. Ball 1 is made of metal and has a greater mass than
Lelechka [254]

Answer:

The drop time ball 1 is less than the drop time of ball 2. A further explanation is provided below.

Explanation:

The net force acting on the ball will be:

⇒ F_{net}=mg-F_r

Here,

F = Force

m = mass

g = acceleration

Now,

According to the Newton's 2nd law of motion, we get

⇒ F_{net} = ma

To find the value of "a", we have to substitute "F_{net}=ma" in the above equation,

⇒ ma=mg-F_r

⇒    a=g-\frac{F_r}{m}

We can see that, the acceleration is greater for the greater mass of less for the lesser mass. Thus the above is the appropriate solution.

8 0
2 years ago
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A light-year is a measure of the astronomical distance that light traverses in a vacuum in 1 year. (a) how many kilometers does
const2013 [10]
<span>A light-year is the total distance that light can travel in 1 year. Since, We know the speed of light (c) in vacuum= 299792458 metres per second And, there are 365.25 days in an year, or t= (365.25*24*60*60) seconds Hence a light-year (d)=c*t =299792458Ă—365.25Ă—24Ă—60Ă—60 metres =9,460,730,472,580,800 metres â‰9.46073Ă—10^15 metres</span>
5 0
3 years ago
The man rolls the cupboard at a steady speed from the lorry to the house. The friction force in the wheels is 40 N. State the fo
tamaranim1 [39]

Answer:

40N

Explanation:

Using the newton's second law of motion

\sum Fx = max

Fm - Ff = max

Fm is the applied force

Ff is the frictional force

m is the mas of the cupboard

ax is the acceleration

Since the speed from the lorry is steady, ax = 0m/s^2

Also Ff = 40N

Substitute into  the formula;

Fm - 40 = m(0)

Fm - 40 = 0

Add 40 to both sides

Fm - 40 + 40 = 0 + 40

Fm = 40N

Hence the force with which the man applied to push is 40N

4 0
3 years ago
What energy transformation occurs when a skydiver first jumps from a plane
d1i1m1o1n [39]
The skydiver jumping from a plane high up in the sky would most likely experience various energy transformation. For starters, it would undergo a very large gravitational potential energy because of its much higher elevation. After jumping, this energy would eventually transform to kinetic energy due to the force exerted by the gravity.
3 0
3 years ago
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