Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is 
The value for static friction is 
Explanation:
From the question we are told that
The mass of the clock is 
The first horizontal force is 
The second horizontal force is 
Generally the static frictional force is equal to the first horizontal force
So

=> 
=> 
Generally the kinetic frictional force is equal to the second horizontal force
So



Answer:
The wires are connected to both terminals of the battery, so they form a closed loop. Most circuits have devices such as light bulbs that convert electrical energy to other forms of energy. ... When the switch is turned on, the circuit is closed and current can flow through it.
Explanation:
Answer:
Fundamental quantities are the base quantities of a unit system, and they are defined independent of the other...
• Derived quantities are based on fundamental quantities, and they can be given in terms of fundamental quantities.
• In SI units, derived units are often given names of people such as Newton and Joule.
Explanation:
<h3>Question:</h3>
•What is the all time speed record for completing the iditarod?
Answer:
•In 2016, Dallas broke his own record, finishing in 8 days, 11 hours, 20 minutes and 16 seconds. In 2017, Mitch Seavey broke all previous records by finishing in 8 days, 3 hours, 40 minutes and 13 seconds, which currently stands as the fastest winning time for the Iditarod.
Explanation:
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For a current-carrying wire running perpendicular to a magnetic field, the magnetic force acting on the wire is given by:
F = ILB
F = magnetic force, I = current, L = wire length, B = magnetic field strength
Given values:
F = 0.60N, L = 1.0m, B = 0.20T
Plug in and solve for I:
0.60 = I(1.0)(0.20)
I = 3.0A