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kiruha [24]
3 years ago
11

Identify how the energy flows up through the ecosystem. Describe how decomposers help to cycle matter in an ecosystem and their

limitations?
Physics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

Decomposers are organisms that break down dead or decaying organisms, they carry out decomposition, a process possible by only certain kingdoms, such as fungi. Like herbivores and predators, decomposers are heterotrophic, meaning that they use organic substrates to get their energy, carbon and nutrients for growth and development. While the terms decomposer and detritivore are often interchangeably used, detritivores ingest and digest dead matter internally, while decomposers directly absorb nutrients through external chemical and biological processes. Thus, invertebrates such as earthworms, woodlice, and sea cucumbers are technically detritivores, not decomposers, since they must ingest nutrients - they are unable to absorb them externally.

Explanation:

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Which example best illustrates the transfer of energy between two waves?
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Answer:

A) A buoy rises in the water as a boat speeds past.

Explanation:

The passing boat transfers energy in the form of a wave. Other options illustrate other physics concepts like gravity (falling egg) or Newton's law (for every action, there is an equal and opposite reaction).

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3 years ago
A bus starts from village A at 7:00 am and reaches village B at 8:30 am. If the distance between the villages A and B is 60 km.
SVEN [57.7K]

1.1111111111

Explanation:

v=s/t

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s=60km covert to meter=6000

6000/5400=1.11111111

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“Just believe in yourself. Even if you don’t pretend that you do and, and some point, you will.”

Explanation:

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The SI unit of power is the
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A football punter wants to kick the ball so that it is in the air for 4.5 s and lands 50 m from where it was kicked. Assume that
irakobra [83]

Answer:

(a) The angle of projection is 63 degree.

(b) The velocity of projection is 24.5 m/s.

Explanation:

Height, h = 1 m

horizontal distance, d = 50 m

time, t = 4.5 s

Let the initial velocity is u and the angle is A.

(a) Horizontal distance = horizontal velocity x time

50 = u cos A x 4.5

u cos A = 11.1 .....(1)

Use second equation of motion in vertical direction

h = u t + 0.5 gt^2\\\\- 1 = u sin A \times 4.5 - 0.5 \times 9.8\times 4.5^2\\\\u sin A = 21.8 ..... (2)

Divide (2) by (1)

tan A = 1.97

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(b) Substitute the value of A in equation (2)

u x sin 63 = 21.8

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