I'm just taking a self educated guess of A sorry if I'm wrong :C
Answer: V=67.2 L
Explanation:
For this problem we will need to use the Ideal Gas Law.
Ideal Gas Law: PV=nRT
P=1.00 atm (STP)
V=?
n=3.00 mol
R=0.08206Latm/Kmol
T=273.15 K (STP)
To find V, we would manipulate the equation to V=nRT/P
With significan figures, our answer is V=67.2 L.
Answer:
Two electrons each!
Explanation:
The question pretty much requires us to find the oxidation number of Zinc in the compound.
Zn3P2
Following oxidation number rules;
O.N of Zn3P2 = 0
.Since phosphorus has valence of 5, it needs three more electrons to achieve its octet state. Hence;
Oxidation number of P = -3
Let oxidation number of Zn = x
We have;
3x + 2 (-3) = 0
3x + (-6) = 0
3x = 6
x = 6/3 = 2
This means each zn electrons lost 2 electrons.
When a physical change occurs, the arrangement of particles within the substance may change, but the atoms in the molecules remain bonded together.
