When
Aldehyde is reacted with
Alcohol in the presence of
acid the it gives
Hemiacetal, Hemiacetal on further reaction with acid and alcohol gives
Acetal.
In given problem the aldehyde given is
P<span>
henylacetaldehyde and alcohol is
Methanol. The reaction is done stepwise as shown below,</span>
The balanced equation for the above reaction is as follows;
2Ca + O₂ ---> 2CaO
stoichiometry of Ca to O₂ is 2:1
we first need to find the limiting reactant
number of Ca moles - 6.84 mol
number of O₂ moles - 4.00 mol
if Ca is the limiting reactant
if 2 mol of Ca reacts with 1 mol of O₂
then 6.84 mol of Ca reacts with - 6.84 / 2 = 3.42 mol of O₂
this means that Ca is the limiting reactant and O₂ is in excess
therefore amount of CaO produced depends on amount of limiting reactant present
stoichiometry of Ca to CaO is 2:2
number of moles of Ca reacted = number of CaO moles formed
number of moles of CaO formed - 6.84 mol
answer is 6.84 mol
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Answer:
See explanation below
Explanation:
First of all, a Diels Alder reaction is very useful to synthetize rings of 6 carbons. In order to do this, we need two reactants. A dienophile and a conjugate diene.
The conjugate diene, is usually a 4 or 5 carbons, with two double bonds, both conjugate and the dienophile, usually have one double bond and an withdrawing atractor group on 1 carbon.
We already have the product here, which is a ring of 6 carbons, with a double bond and chlorine in two carbons. The only way to do this is putting a conjugate diene of 4 carbons, and a dienophile with 3 carbons and 2 chlorines.
The mechanism of reaction is in the attached picture.
Hope this helps
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