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3 years ago

_Ch7H16+_O2=_CO2+_H2O balancing the equation

Chemistry

1 answer:

inysia [295]3 years ago

4 0

Answer:

0,11,7,8

Explanation: hope this helps!

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Acids or bases can be tested by chemical_________

DedPeter [7]

Answer:

acids or bases can be tested

by chemical indicators

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2 years ago

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suppose medical records indicate that the length of newborn babies (in inches) is normally distributed with a mean of 20 and a s

Tanya [424]

Answer:

0.6826 (68.26%)

Explanation:

1) Find the z-scores:

z = [X - μ ] / σ

a) z-score for 22.6 inches length

X = 22.6
μ = 20
σ = 2.6

z = [ 22.6 - 20 ] / 2.6 = 1.00

b) z-score for 17.4 inches length

X = 17.4
μ = 20
σ = 2.6

z = [ 17.4 - 20 ] / 2.6 = - 1.00

2) Probability

Then, you have to find the probability that the length of an infant is between - 1.00 and 1.00 standards deviations (σ) from the mean (μ).

That is a well known value of 68%, which is part of the 68-95-99.7 empirical rule.

The most exact result is obtained from tables and is 68.26%:

1 - P (z ≥ 1.00) - P (z ≤ - 1.00) = 1 - 0.1587 - 0.1587 = 0.6826 = 68.26%

5 0

3 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

Answer: The mass of original oxalic acid sample is 6.75 grams

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

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3 years ago

What does an emission spectrum look like?

aniked [119]

Answer:

It should be B

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3 years ago

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Precipitation that falls into rivers lakes and streams is called

balu736 [363]

Answer:

a runoff

Explanation:

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3 years ago