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4 years ago

0. A 1700-W machine operates at 120 V. What i

Physics

1 answer:

kap26 [50]4 years ago

4 0

Option D

The resistance in machine is 8.5 ohms

Solution:

Given that,

Power = 1700 W

Voltage = 120 V

We have to find the resistance in machine

The formula used is:

$P = \frac{V^2}{R}$

Where,

"P" is the electric power and "V" is the voltage and "R" is the resistance

Substituting the given values we get,

$1700 = \frac{120^2}{R}\\\\1700 = \frac{14400}{R}\\\\R = \frac{14400}{1700}\\\\R = \frac{144}{17}\\\\R = 8.47 \approx 8.5$

Thus resistance in machine is 8.5 ohms

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Researchers are investigating whether people who exercise with a training partner have a greater increase, on average, in target

liubo4ka [24]

[NOTE: THIS IS INCOMPLETE QUESTION. THE COMPLETE QUESTION: Researchers are investigating whether people who exercise with a training partner have a greater increase, on average, in targeted exercise intensity compared with people who exercise alone. Two methods of collecting data have been proposed. Method i: recruit volunteers who are willing to participate. Randomly assign each participant to exercise with a training partner or to exercise alone. Method ii: select a random sample of people from all the people who exercise at a community fitness center. Ask each person in the sample whether they use a training partner, and use the response to create the two groups.]

In method I, the population generalization is almost random, hence it uses a random sample. In method II, the population generalization is less random, hence it uses a biased sample.

In terms of population generalization, the two methods differ. In method I where participants randomly assign each participant to exercise with a training partner or to exercise alone from the volunteers who are willing to participate, the sampling method is almost random as it includes people who are exercise regularly (in majority) and those who do not exercise regularly. Due to the randomized nature of the sample, the results can be applied to the entire population.

In method II where sampling is done by selecting a random sample of people from all the people who exercise at a community fitness center and determining if they use a training partner or exercise alone to create the two groups. As the people included in the sample are less random as they work out regularly at the fitness center. Hence, the sample is biased as it does not include any representation of people who do not work out regularly. The results cannot be used to apply to the entire population generalization.

Therefore, Population generalization is generalizing the population into two categories out of which one is more random in selection than the other.

Learn more about Population generalization, refer: brainly.com/question/26238937

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4 0

1 year ago

Pleassseeee help meeeee

lukranit [14]

Answer:

maybe the rear wheel axel rusted not sure

7 0

3 years ago

You’re standing at the highest point on the Moon, 10,786 mm above the level of the Moon’s mean radius. You’ve got a golf club an

Anna71 [15]

Answer:

A) v = 1,675 10³ m / s , B) r₂ = 11,673 10⁶ m

Explanation:

A) This exercise we must use Newton's second law, where the forces of gravity are the Moon

F = m a

acceleration is centripetal

a = v² / r

force is the force of universal attraction

F = G m M / r²

we substitute

G m M / r² = m v² / r

v² = G M / r

distance

r = R_moon + h

r = 1.74 10⁶ +1.0786 10⁴

r = 1,750786 10⁶ m

we calculate

v = √ (6.67 10⁻¹¹ 7.36 10²² / 1.75 10⁶)

v = √ (2,8052 10⁶)

v = 1,675 10³ m / s

B) let's use energy conservation

Starting point. In the mountain

Em₀ = K + U = ½ m v² + G m M / r

Final point. Where the speed is zero

$Em_{f}$ = U = G mM / r₂

Em₀ = Em_{f}

½ m v² + G m M / r = G mM / r₂

1 / r₂ = (½ v₂ + G M / r) / GM

let's calculate

1 / r₂ = (½ (1,675 10³)² + 6.67 10⁻¹¹ 7.36 10²² / 1.75 10⁶) /(6.67 10⁻¹¹ 7.36 10²²)

1 / r₂ = (1,4028 10⁶ + 2,805 10⁶) / 49.12 10¹¹

1 / r₂ = 8.5664 10⁻⁷

r₂ = 11,673 10⁶ m

6 0

3 years ago

A mercury thermometer is constructed as

Tamiku [17]

Answer:

The change in height of the mercury is approximately 2.981 cm

Explanation:

Recall that the formula for thermal expansion in volume is:

$\frac{\Delta V}{V_0} =\alpha_V\, \Delta\, T\\\Delta V = V_0\,\, \alpha_V\,\,\Delta C$

from which we solved for the change in volume $\Delta V$ due to a given change in temperature $\Delta T$

We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:

$V_0=\frac{4}{3} \pi \, R^3\\V_0=\frac{4}{3} \pi \, (0.12\,cm)^3\\V_0=0.007238\,cm^3$

Therefore, the change in volume with a change in temperature of 36°C becomes:

$\Delta V = V_0\,\, \alpha_V\,\,\Delta C\\\Delta V = 0.007238229\, cm^3\,(0.000182)\,(36)\\\Delta V=0.0000474248\, cm^3$

Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):

$V_{cyl}=\pi r^2\,h\\h =\frac{V_{cyl}}{\pi r^2} \\h=\frac{0.0000474248\, cm^3}{\pi \, (0.00225\,cm)^2} \\h=2.98188 \,cm$

8 0

3 years ago

How do snails support and protect themselves without a skeleton

snow_tiger [21]

Surely it is their shell that protects them. They hide beneath it

3 0

3 years ago

Read 2 more answers