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3 years ago

As a hydrated compound is heated, it decreases in

1 answer:

8 0

A hydrated substance will decrease in mass when heated since the water is being boiled away.

I hope this helps. Let me know if anything is unclear.

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Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici

Roman55 [17]

2KNO3 -> 2KNO2 + O2. Hope this helps!

5 0

2 years ago

Read 2 more answers

Which is a form of heat transfer that is reduced by using a potholder when taking a hot dish out of an oven? Please answer quick

Angelina_Jolie [31]

Answer:

i belive your talking about Conduction

Explanation:

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2 years ago

Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph

meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

<em>Volume of the acid, V = 250 mL</em>
<em>pH of the acid, = 2.4</em>

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

$H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398$

The molarity of the nitric acid is calculated as follows;

$= 0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M$

The number of moles of the nitric acid is calculated as follows;

$moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.$

The molar mass of nitric acid is calculated as;

$HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol$

The mass of the nitric acid contained in the calculated number of moles is calculated as;

$mass = moles\ \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g$

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

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1 year ago

When 8.70 kJ of thermal energy is added to 2.50 mol of liquid methanol, it vaporizes. Determine the heat of vaporization in kJ/m

Anni [7]

Answer:

The heat of vaporisation of methanol is "3.48 KJ/Mol"

Explanation:

The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation

When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.

Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is = $\frac{8.7}{2.5}KJ$

= 3.48 KJ

So, the heat of vaporization $\delta H_{vap} = 3.48KJ/Mol$

Therefore, the heat of vaporization of methanol is 3.48KJ/Mol

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2 years ago

Help me plz #10 would appreciate it

DaniilM [7]

C I’m pretty sure. I can explain just lmk

7 0

2 years ago