The question is incomplete, the complete question is;
Why is a terminal alkyne favored when sodium amide (NaNH2) is used in an elimination reaction with 2,3-dichlorohexane? product. A) The terminal alkyne is more stable than the internal alkyne and is naturally the favored B) The terminal alkyne is not favored in this reaction. C) The resonance favors the formation of the terminal rather than internal alkyne. D) The strong base deprotonates the terminal alkyne and removes it from the equilibrium.
E) The positions of the Cl atoms induce the net formation of the terminal alkyne.
Answer:
E) The positions of the Cl atoms induce the net formation of the terminal alkyne.
Explanation:
In this reaction, sterric hindrance plays a very important role. We know that sodamide is a strong base, it tends to attack at the most accessible position.
The first deprotonation yields an alkene. The strong base attacks at the terminal position again and yields the terminal alkyne. Thus the structure of the dihalide makes the terminal hydrogen atoms most accessible to the base. Hence the answer.
Answer:
- covalent bond
- polar covalent bond
- ionic bond
- metallic bond
Explanation:
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The moon surface is
visible to an observer on earth due to the gravitational force that attracts the
moon to the earth. The more massive the body is, the more the smaller body is
attracted to the larger body. We can only see the side of the moon due to the
speed at which the moon rotates.
<span>A reversible reaction is a chemical change in which the products can be converted back to the original reactants under suitable conditions.</span><span> In a reversible reaction, changing the reaction conditions e.g. concentration, pressure or temperature will change the net direction the reaction goes i.e. more to the right (forward) or more to left (backward).<span>It also means a reversible reaction does not go to completion in either direction and all components, original reactants or ensuing products, ALL co-exist in the reaction mixture (see notes on chemical equilibrium).</span></span><span><span>This means the reaction can go in either direction i.e.</span><span> <span>A + B ==> C + D or C + D ==> A + B</span></span></span><span><span>A reversible reaction is shown by the sign ,</span><span> <span>a half-arrow to the right (direction of forward reaction), </span><span>and a half-arrow to the left (direction of backward reaction).</span><span>It is really important you understand that the terms right & left AND forward & backward are used in the context of how the equation is presented.</span></span></span><span><span>Most reactions are not reversible (irreversible) and have the usual complete arrow only pointing to the right.</span>
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