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SCORPION-xisa [38]
3 years ago
9

Humanity is faced by many challenges and problems.

Physics
1 answer:
Nesterboy [21]3 years ago
3 0

Answer:

yessjdjdjsnanmamNznanabbznzxkd

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A satellite revolves around a planet at an altitude equal to the radius of the planet. the force of gravitational interaction be
padilas [110]
Let
M = the mass of the planet
n = the mass of the satellite.
r = the radius of the planet

When the satellite is at a distance r from the surface of the planet, the distance between the centers of the two masses is 2r.
The gravitational force between them is
f_{0} = \frac{GMm}{(2r)^{2}} = \frac{1}{4} ( \frac{GMm}{r^{2}} )
where
G =  the gravitational constant.

When the satellite is on the surface of the planet, the distance between the two masses is r.
The gravitational force between them is
f_{4} =   \frac{GMm}{r^{2}} =4f_{0}

Answer:  f_{4} = 4f_{0}

5 0
4 years ago
Read 2 more answers
At a particular instant the magnitude of the momentum of a planet is 2.60 × 10^29 kg·m/s, and the force exerted on it by the sta
aleksley [76]

Answer:

F=(-4.8*10^22,0,0) N

Explanation:

<u>Given  :</u>

We are given the magnitude of the momentum of the planet and let us call this momentum (p_now) and it is given by p_now = 2.60 × 10^29 kg·m/s. Also, we are given the force exerted on the planet F = 8.5 × 10^22 N. and the angle between the planet and the star is Ф = 138°

Solution :

We are asked to find the parallel component of the force F The momentum here is not constant, where the planet moving along a curving path with varying speed where the rate change in momentum and the force may be varying in magnitude and direction. We divide the force here into two parts: a parallel force F to the momentum and a perpendicular force F' to the momentum.  

The parallel force exerted to the momentum will speed or reduce the velocity of the planet and does not change its moving line. Let us apply the direction cosines, we could obtain the parallel force as next  

F=|F|cosФp            (1)

Where the parallel force F is in the opposite direction of p as the angle between them is larger than 90°. Now we can plug our values for 0 and I F I into equation (1) to get the parallel force to the planet  

F=|F|cosФp

 =-4.8*10^22 N*p

<em>As this force is in one direction, we could get its vector as next  </em>

F=(-4.8*10^22,0,0) N

F=(0,-4.8*10^22,0) N

F=(0,0-4.8*10^22) N

The cosine of 138°, the angle between F and p is, is a negative number, so F is opposite to p. The magnitude of the planet's momentum will decrease.

8 0
3 years ago
Which element is not part of the rhetorical triangle designed by Aristotle? speaker credibility audience emotion content logic l
ser-zykov [4K]
The correct answer is this one: "length of address." The element that is not part of Aristotle's rhetorical triangle is the length of the address. The rhetorical triangle of Aristotle are the logos, pathos, and ethos. Logos is the logic, Pathos is the audience emotion, Ethos is the speaker's credibility.
3 0
3 years ago
Read 2 more answers
Calculate the period of a satellite orbiting the moon, 94 km above the moon's surface. ignore effects of the earth. the radius o
In-s [12.5K]

First we calculate the effective radius R:

R = 1740+94 = 1834 km = 1.834E6 m 

 

Then taking the mass of the moon:<span>
M = mass of moon = 7.348E22 kg </span>

 

We then calculate the period using the formula:<span>

<span>T = 2π√[R³/(GM)] = 7049.3 sec = 1.96 hr</span></span>

4 0
3 years ago
Read 2 more answers
A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 31.8 ◦C . In an attempt to cool the liquid, wh
Shtirlitz [24]

Answer:

Explanation:

mass of liquid m₁ = 161 g

temperature t₁ = 31.8

final temperature t₂ = 28.8

Let m g of ice melted to cool the liquid

heat gained = mass x latent heat of fusion + mass x loss of temp x s heat of water

= m x 80 + m x 1 x ( 31.8 - 28.8 ) ( latent heat of ice = 80 cals/g )

= 83 m

heat lost  = 161 x 1 x ( 31.8 - 28.8 ) ( specific heat of water = 1 cal / g / k )

= 161 x 3

heat lost = heat gained

83 m = 161 x 3

m = 5.82 g

mass of remaining ice = 131 - 5.82

= 125.18 g

4 0
4 years ago
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