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Agata [3.3K]
3 years ago
6

The circumference of the earth is 40,000 km. The distance from the

Physics
1 answer:
Finger [1]3 years ago
7 0

Answer:

The distance from the North Pole to the equator is 1*10^{7}m.

Explanation:

Circumference of Earth = 40,000 km    ......................(1)

Distance from the North Pole to the Equator is =  1/4th of the Circumference of Earth  ......................  (2)

Let Distance from the North Pole to the Equator be  d ,

the equation formed will be ,

d = 1/4 * Circumference of Earth       ........(3)......... ( from equation 1 )

put the value of Circumference of Earth in equation (3),

d = 1/4 * 40,000  km

d = 10,000 km

converting km to m ,

d = 10,000 * 10^{3} m

d =  1 * 10^{7} m

The distance from the North Pole to the equator is 1*10^{7}m.

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A 60.00-cm guitar string under a tension of 50.000 N has a mass per unit length of 0.100 00 g/cm chegg
Evgen [1.6K]

Fundamental frequency,

f=v2l=T/μ−−−−√2l

=(50)/0.1×10−3/10−22×0.6−−−−−−−−−−−−−−−−−−−√

=58.96Hz

Let, n th harmonic is the hightest frequency, then

(58.93)n = 20000

∴N=339.38

Hence, 339 is the highest frequency.

∴fmax=(339)(58.93)Hz=19977Hz.

<h3>What is frequency?</h3>

In physics, frequency is the number of waves that pass a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also simple harmonic motion and angular velocity.

learn more about frequency refer:

brainly.com/question/254161

#SPJ4

7 0
2 years ago
Classify the properties as extensive or intensive: mass density; color volume; total energy; temperature; melting point
m_a_m_a [10]

Answer:

Intensive properties

Density

Color

temperature

Melting point

Extensive properties

Mass

Volume

Total Energy

Explanation:

Intensive properties:  In Physics, Intensive properties which are not depend of the amount of matter in a sample, It only depends of the type of matter, some examples of intensive properties are:

1. Density: It is a intensive property. It can explain better with a example:  the water density is 1000 kg/m3, So if we have 1 liter or 1000 liters of water  the density will be the same for the two samples.

2. Color: Solid sodium chloride is white. If you have 2 samples the first recipient  with 2 kilograms of NaCl and the second with 10 kilograms of NaCl. The color of the substance does not depend on the amount of the substance.

As was mentioned before the same theory is applied to temperature and melting point concepts.

On the other hand,

Extensive properties are properties of the matter which depend on the amount of matter that is present in the system or sample. some examples are:

1. Mass: It is a property that measures the amount of matter that an object contains. For example, 10 kilograms of solid Copper contains a higher mass than 2 kilograms of the same metal.  

2. Volume: It is a property which measures the space occupied by an object or a substance. For example, the space occupied by a glass of milk is lower than the space occupied by a bottle of milk, Then the volume of the glass of milk is lower than the volume of the bottle of milk.

3. Finally the total energy is contained in molecules and atoms that constituted systems  so, if the amount of matter increases the number of molecules too, then the total energy will increase.

I hope it helps you.

6 0
3 years ago
What is the centripetal acceleration of a small laboratory centrifuge in which the tip of the test tube is moving at 19.0 meters
Volgvan
A_central = v^2/r = (19)^2/10 = 36.1 m/s^2
7 0
3 years ago
Read 2 more answers
Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27
densk [106]

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n\times\dfrac{m}{V_{c}\times N_{A}}

n=\dfrac{\rho\timesV_{c}\times N}{m}....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=\dfrac{1}{\dfrac{12.5}{4.27}+\dfrac{87.5}{6.35}}\times100

\rho=5.98

We calculate the mass of the alloy

m=\dfrac{1}{\dfrac{12.5}{61.4}+\dfrac{87.5}{125.7}}\times100

m=111.15

Put the value into the equation (I)

n=\dfrac{5.9855\times(0.395\times10^{-9}\times10^{2})^3\times6.023\times10^{23}}{111.15}

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

5 0
3 years ago
A ball is thrown straight upward on the Moon. Is the maximum height it reaches less than, equal to, or greater than the maximum
IgorC [24]
The maximum height on moon is HIGHER than the maximum height on earth
6 0
3 years ago
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