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Agata [3.3K]
3 years ago
6

The circumference of the earth is 40,000 km. The distance from the

Physics
1 answer:
Finger [1]3 years ago
7 0

Answer:

The distance from the North Pole to the equator is 1*10^{7}m.

Explanation:

Circumference of Earth = 40,000 km    ......................(1)

Distance from the North Pole to the Equator is =  1/4th of the Circumference of Earth  ......................  (2)

Let Distance from the North Pole to the Equator be  d ,

the equation formed will be ,

d = 1/4 * Circumference of Earth       ........(3)......... ( from equation 1 )

put the value of Circumference of Earth in equation (3),

d = 1/4 * 40,000  km

d = 10,000 km

converting km to m ,

d = 10,000 * 10^{3} m

d =  1 * 10^{7} m

The distance from the North Pole to the equator is 1*10^{7}m.

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A person on a merry-go-round makes a complete revolution in about 3.17 s.
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2 years ago
Three resistances 2 ohm ,3ohm and 5 ohm are connected in parallel and a
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The potential difference across 3 Ohm resistor is 20V.

The resistors are connected in parallel which means all the three resistances have a fully potential difference of 20V.

7 0
3 years ago
A jet can travel the 6000 km distance between washington,
Andrei [34K]
<span> d = r*t is the basic distance equation
 d = 6000 km
 t with the tail wind = 6 hr
 r with the tail wind = speed of the plane + wind speed = s + w
 t with the head wind = 7.5 hr
 r with the head wind = speed of the plane - wind speed = s-w
 (s+w)*6 = 6000
 (s-w)*7.5 = 6000
 s + w = 1000
 s - w = 800
</span><span> 2s = 1800
 s = 900 km/h
 s + w = 1000
 w = 100
 Check the anwer by calculating the return trip.
 (900-100) * 7.5 = 800 * 7.5
 800 * 7.5 = 6000 km
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6 0
3 years ago
The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
puteri [66]

Answer:

t=5.3687\ s  is the time taken by the car to accelerate the desired range of the speed from zero at full power.

Explanation:

Given:

Range of speed during which constant power is supplied to the wheels by the car is 0\ mph\ to\ 70\ mph.

  • Initial velocity of the car, v_i=0\ mph
  • final velocity of the car during the test, v_f=32\ mph=14.3052\ m.s^{-1}
  • Time taken to accelerate form zero to 32 mph at full power, t=1.2\ s
  • initial velocity of the car, u_i=0\ mph
  • final desired velocity of the car, u_f=64\ mph=28.6105\ m.s^{-1}

Now the acceleration of the car:

a=\frac{v_f-v_i}{t}

a=\frac{14.3052-0}{1.2}

a=11.921\ m.s^{-1}

Now using the equation of motion:

u_f=u_i+a.t

64=0+11.921\times t

t=5.3687\ s is the time taken by the car to accelerate the desired range of the speed from zero at full power.

8 0
3 years ago
Free brainlyest. if get thes quston right Devlin recorded the number of days of rain for his town over three months. The bar gra
m_a_m_a [10]

Answer:

Weather is the conditions (temperature, wind etc.) at a given time, like on that day. Climate, which is what his data would show, is the conditions over an extended period of time like the 3 months he collected data

8 0
2 years ago
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