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grigory [225]
3 years ago
15

dissolving sugar in water is a physical change but heating sugar to form a caramel is a chemical change .Explain​

Chemistry
1 answer:
kramer3 years ago
8 0

Explanation:

Also, the water molecules are not changed when sugar is dissolved in water to form a sugar solution. We can easily get back the sugar by evaporation of water from the sugar solution. The evaporated water can then be condensed to recover the water also. Hence, it is a physical change and not a chemical change.

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How many electrons do nonmetal atoms tend to gain when forming ions?
Delvig [45]

Answer:

b

Explanation:

that the answer to that question

5 0
3 years ago
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a certain mass of gas occupies 2240 volume at a pressure of 760mkhg and temperature of 320k.find it's new volume if the preddure
natita [175]

The new volume : V₂ =  2454.8 L

<h3>Further explanation</h3>

Given

V₁=2240 L

P₁=760 mmHg

T₁=320 K

P₂=700 mmHg

T₂=323 K

Required

Volume V₂

Solution

Combined gas law :

P₁V₁/T₁=P₂V₂/T₂

Input the value :

760 mmHg x 2240 L /320 K = 700 mmHg x V₂/323 K

V₂=(P₁V₁T₂)/P₂T₁

V₂=(760 x 2240 x 323)/(700 x 320)

V₂ = 2454.8 L

6 0
3 years ago
Consider a piece of gold jewelry that weighs 9.85 g and has a volume of 0.675 cm3 . The jewelry contains only gold and silver, w
AlekseyPX

Answer:

61.5096 %

Explanation:

Let the amount of gold in the jewelry = x g

Let the amount of silver in the jewelry = y g

Total mass of jewelry = 9.85 g

So,

x + y = 9.85 g    .................................1

Density = Mass / Volume

Given that:

Density of gold = 19.3 g/cm³

Thus, volume is:

Volume = Mass / Density = x / 19..3 cm³

Given that:

Density of silver = 10.5 g/cm³

Thus, volume is:

Volume = Mass / Density = y / 10.5 cm³

The total volume of the jewelry = 0.675 cm³

So,

\frac {x}{19.3}+\frac {y}{10.5}=0.675

Or,

10.5 x + 19.3 y = 136.78875  ................2

Solving 1 and 2, we get that:

<u>x = 6.0587 g</u>

<u>y = 3.7913 g</u>

So, mass % of gold:

<u>Mass % = (6.0587 / 9.85)×100 = 61.5096 %</u>

7 0
3 years ago
PLEASE ANSWER!!!!!!!! WILL MARK BRAILIEST
Mariana [72]
9.Pubchem
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6 0
3 years ago
How many milliliters of water are needed to prepare a 3.5M solution of NaOH if you have .5mol of the solute
Mamont248 [21]

Answer:

1335.12 mL of H2O

Explanation:

To calculate the mililiters of water that the solution needs, it is necessary to know that the volume of the solution is equal to the volume of the solute (NaOH) plus the volume of the solvent (H2O).

From the molarity formula we can first calculate the volume of the solution:

M=\frac{solute moles}{solution volume}

Solutionvolume=\frac{solute moles}{M} =\frac{5mol}{3.5\frac{mol}{L} } =1.429L

The volume of the solution as we said previously is:

Solution volume = solute volume + solvent volume

To determine the volume of the solute we first obtain the grams of NaOH through the molecular weight formula:

MW=\frac{mass}{mol}

Mass=MW*mol=39.997\frac{g}{mol} *5mol=199.985g

Now with the density of NaOH the milliliters of solute can be determined:

d=\frac{mass}{volume}

Volume=\frac{mass}{d} =\frac{199.985g}{2.13\frac{g}{mL} } =93.88mL of NaOH

Having the volume of the solution and the volume of the solute, the volume of the solvent H2O can be calculated:

Solvent volume = solution volume - solute volume

Solvent volume = 1429 mL -  93.88 mL = 1335.12 mL of H2O

7 0
4 years ago
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