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kirza4 [7]
3 years ago
8

14. Determine the kinetic energy of a 1000-kg roller coaster car that is moving with a speed of

Physics
2 answers:
ElenaW [278]3 years ago
6 0

Answer:

<h2>200,000 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1000 \times  {40}^{2}  \\  = 500 \times 400

We have the final answer as

<h3>200,000 J</h3>

Hope this helps you

zzz [600]3 years ago
3 0

Hello!!

Sorry to contradict the before answer, but he's wrong.

The formula is correct:

k = 1/2 * mv²

If we replace it with our data:

k = 1/2 * (1000 kg) (40 m/s)²

<u>Here is the problem</u>, <u>40^2 is = 1600</u>, so the result is wrong:

k = 500 Kg * 1600 m²/s²

And if we resolve it:

k = 800 000 Joules

Then the kinetic energy of the roller coaster car is <u>800 000 Joules.</u>

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Energy transformation in wound spring of a toy car?<br>give your own answrr​
BaLLatris [955]

Answer:

The work done in winding the spring gets stored in the wound up spring in the form of elastic potential energy (i.e potential energy due to change in shape). ... During this process, the potential energy stored in it gets converted to kinetic energy. This turns the wheels of the toy car.

Explanation:

7 0
3 years ago
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lys-0071 [83]

Answer:

Explanation:

The velocity is 340, but the distance is not. Here's how you do this:

You need to find out the velocity of the that sound in that temp which has a formula of

v = 331.5 + .606T where T is the temp in Celcius. Filling in and using the correct number of sig dig:

v = 331.5 + .606(20) and

v = 331.5 + 10 and

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d = 340(2.00) so

d = 680 m

3 0
3 years ago
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Please help!!!!!!!!!!!!! i will give brainly
liq [111]

Answer:

1.) strength or energy to do an action or movement

2.)an object will jot change its motion unless acted on by an unbalanced force

8 0
3 years ago
A Juggler is juggling a uniform rod one end of which is coated in tar and burning. He is holding the rod by the opposite end and
lyudmila [28]

The vertical speed of the rod varies inversely as the rotational speed for a given number of complete rotations

The equation that gives the vertical velocity, v₀ is  \, \underline{v_0=  \dfrac{ g \cdot \pi \cdot n}{  \omega_0   }}

Reason:

<em>From a similar question, the given parameters appear to be correctly given as follows;</em>

<em>The vertical speed of the rod = v₀</em>

<em>Angular velocity of the = ω₀</em>

Required;

The value of, v₀, so that the rod has made exactly, <em>n</em>, number of turns when it returns to his hand

Where;

n = An integer

Solution;

The time the rod spends in the air is given as follows;

Height, \ h = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2

Where;

g = Acceleration due to gravity

t = Time of motion

When the rod returns to his hand, we have, h = 0, therefore;

0 = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2

u \cdot t = \dfrac{1}{2} \cdot g \cdot t^2

t^2 =  \dfrac{u \cdot t }{\dfrac{1}{2} \cdot g } =   \dfrac{2 \cdot u \cdot t }{g }

Time, \ t =    \dfrac{2 \cdot u  }{g }

We have;

Angular \ velocity, \ \omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{t} \ (required)

\omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{  \dfrac{2 \cdot v_0  }{g }} =  \dfrac{ g \cdot \pi \cdot n}{  v_0 }

Therefore;

The \ vertical \ velocity, \, \underline{v_0=  \dfrac{ g \cdot \pi \cdot n}{  \omega_0   }}

Learn more here:

brainly.com/question/14140053

4 0
3 years ago
Light shines through a single slit whose width is 5.7 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m awa
polet [3.4K]

Answer: 557nm

Explanation:

Visible light has been known to have its wavelengths in the range between 400 to 700 nanometres (nm), or 4*10^-7 to 7*10^-7 m. This wavelength is between infrared and ultraviolet. Infrared has longer wavelengths and while on the other hand ultraviolet has shorter wavelengths. The wavelength of visible light has a frequency of approximately 430 to 750 terahertz (THz).

tanΦ= 0.0039/4 = 9.75*10^-4

Φ= tan^-1 (9.75*10^-4)

Φ= 0.056

λ= (5.7*10^-4) * sin 0.056

λ= 5.57*10^-7m

λ= 557nm

5 0
4 years ago
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