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KonstantinChe [14]
3 years ago
5

Are the objects described here in static equilibrium, dynamic equilibrium, or not in equilibrium at all?

Physics
1 answer:
Brut [27]3 years ago
8 0

Answer:

a) dynamic equilibrium; b) No equilibrium; c) Static equilibrium; d) Dynamic equilibrium; e) Not equilibrium; f) Dynamic equilibrium.

Explanation:

a) In this case, the girder is in dynamic equilibrium, although there is movement it is realized at constant speed therefore there is no acceleration and the sum of forces is equal to zero.

b) There is no equilibrium since the velocity is decreasing it slows the girder, therefore the sum of forces will be equal to the product of mass by acceleration according to newton's second law.

c) In this case, the arms of the person are exercising each 100 lb, in order to keep the barbell stable, this allows the static equilibrium.

d) There is movement but however the jet will move at constant speed without any kind of acceleration, therefore it has a condition of dynamic equilibrium.

e) There is no balance as the rock falls and the acceleration due to gravity causes its speed to increase as it goes down.

f) In this case there is dynamic equilibrium as there was a deceleration movement however this force value given by the deceleration multiplied by the mass is not large enough to be able to move the box, due to the weight of the box plus the friction force between the box and the surface.

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7 0
3 years ago
Assuming a nearly frictionless ride, what can you say about a roller coaster’s potential and kinetic energy from the top to the
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E=K+U
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Since the ride is frictionless, the total mechanical energy E is conserved during the ride. Therefore, at the top of the hill, the potential energy is maximum, because h (the height) is maximum, and this means the kinetic energy is minimum (because the sum of K and U is constant), so the velocity will be minimum. Viceversa, at the bottom of the hill, the potential energy will be minimum (because h is minimum), so the kinetic energy K will be maximum, and the velocity v of the roller coaster will be maximum.
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3 years ago
If the San Andreas Fault moves 200 cm (2 meters) per big earthquake, and plate movement is xx cm/yr (see question above), how ma
weqwewe [10]

Answer:

Option C

80 years

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Since the fault moves at the rate of 2 meters per year, to obtain the number of years it will takes to produce an earth quake, we will have to divide the rate of movement of the fault by the rate of movement of the plate.

Number of years for earthquake = \frac{2}{0.025}= 80 years.

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5 0
4 years ago
there are 5 influencing factors that may affect participation rate in physical activity. can you name them?
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4 years ago
Two horizontal forces are exerted on a large crate. The first force is 317 N to the right. The second force is 173 N to the left
DENIUS [597]

Answer:

A. Refer to the figure.

B. The net force acting on the crate is

F_{net} = F_1 - F_2 = 317 - 173 = 144N

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v = v_0 + at\\6.5 = 0 + 5a\\a = 1.3 m/s^2

Mass of the crate can be found by Newton’s Second Law:

F = Ma\\M = F/a = 144/1.3 = 110.7 kg

7 0
4 years ago
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