Answer: (B) 100
Explanation:
Given that;
Pstatic = 20 psig , hz = 160ft, hf = 20ft
Now total head will be;
T.h = hz + hf
T.h= 160 + 20
T.h = 180ft
Minimum pressure = Psatic + egh
we know that specific weight of water is 62.4 (lb/ft3)
so
P.min = (20 bf/in² ) + (62.4 b/ft³ × 180 fr
P.min = (20 bf/in² ) + ( 62.4 × 180 × 1 ft²/144 in²)
P.min = 20 + 78
P.min = 98 lbf/in²
Therefore the minimum pressure rating (psi) of the piping system is most nearly B) 100
Answer:
The current through each lamp is 0.273 Amperes
Power dissipated in each lamp is 0.082W
Explanation:
Battery v = 1.5 V
Each lamp has resistance, r = 1.1 Ohms
The 5 lamps in series will therefore have total resistance, R = 5 * 1.1 = 5.5 Ohms
The current through each lamp, I = v/R = 1.5 / 5.5 = 0.273 Amperes
Power dissipated in each lamp = I² * r = 0.273² * 1.1 = 0.082W
Well, I do know that polarity affects the voltage.
Answer:
The solution for the given problem is done below.
Explanation:
M1 = 2.0
= 0.3636
= 0.5289
= 0.7934
Isentropic Flow Chart: M1 = 2.0 , 
= 1.8
T1 = 
(1.8)(288K) = 653.4 K.
In order to choke the flow at the exit (M2=1), the above T0* must be stagnation temperature at the exit.
At the inlet,
T02= 
= (1.8)(288K) = 518.4 K.
Q= Cp(T02-T01) = 
= 135.7*
J/Kg.
