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3 years ago

your friend's parents are worried about going over their budget for th month. Which expense would you suggest is NOT a need?

1 answer:

3 0

Things for entertainment aren't needs. For example, designer clothes, the new iPhone that just came out, fancy dining, that expensive shirt that has the same model somewhere cheaper, and sports cars are all wants, not needs.

Needs are like water, a shelter to live in, food, clothing, and running electricity. Water is essential for survival, since you could die of thirst in 2 days. A shelter will protect you from insects, weather, and uninvited guests. Living without food will kill you in 2 weeks, as you need food for energy and so let your body repair itself faster if you got injured. You need clothing to keep you warm and to cover your private parts. Running electricity is needed because electricity makes most of your needs easier to acquire.

I hope this helps! Good luck!

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In an orthogonal cutting operation, the tool has a rake angle = 12°. The chip thickness before the cut = 0.32 mm and the cut yie

Snezhnost [94]

Answer:

The shear plane angle and shear strain are 28.21° and 2.155 respectively.

Explanation:

(a)

Orthogonal cutting is the cutting process in which cutting direction or cutting velocity is perpendicular to the cutting edge of the part surface.

Given:

Rake angle is 12°.

Chip thickness before cut is 0.32 mm.

Chip thickness is 0.65 mm.

Calculation:

Step1

Chip reduction ratio is calculated as follows:

$r=\frac{t}{t_{c}}$

$r=\frac{0.32}{0.65}$

r = 0.4923

Step2

Shear angle is calculated as follows:

$tan\phi=\frac{rcos\alpha}{1-rsin\alpha}$

Here, $\phi$ is shear plane angle, r is chip reduction ratio and $\alpha$ is rake angle.

Substitute all the values in the above equation as follows:

$tan\phi=\frac{rcos\alpha}{1-rsin\alpha}$

$tan\phi=\frac{0.4923cos12^{\circ}}{1-0.4923sin12^{\circ}}$

$tan\phi=\frac{0.48155}{0.8976}$

$\phi=28.21^{\circ}$

Thus, the shear plane angle is 28.21°.

(b)

Step3

Shears train is calculated as follows:

$\gamma=cot\phi+tan(\phi-\alpha)$

$\gamma=cot28.21^{\circ}+tan(28.21^{\circ}-12^{\circ})$ $\gamma = 2.155$ .

Thus, the shear strain rate is 2.155.

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Explanation:

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Answer:

True

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