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4 years ago

5

How long should the shafts remain in the furnace to achieve a desired centerline temperature of 800K? 2) Determine the temperatu

re gradient in the shaft at the outer surface of the shaft at the initial time when the steels enter the furnace? Note, the r coordinate extends along the direction from the center to outside.

1 answer:

Phantasy [73]4 years ago

6 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is appli

Scrat [10]

Answer:

$X_t=2.17391304*10^{-4}$

$X_r=2.89855072*10^{-4}$

$e_t=0.0026$

$e_r=0.0035$

Explanation:

From the question we are told that:

Dimension $12*12$

Thickness $l_t=5mm=5*10^-3$

Normal tensile force on top side $F_t= 15kN$

Normal tensile force on right side $F_r= 20kN$

Elastic modulus, $E=115Gpap=>115*10^9$

Generally the equation for Normal Strain X is mathematically given by

$X=\frac{Force}{Area*E}$

Therefore

For Top

$X_t=\frac{Force_t}{Area*E}$

Where

$Area=L*B*T$

$Area=12*10^{-2}*5*10^{-3}$

$Area=6*10^{-4}$

$X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}$

$X_t=2.17391304*10^{-4}$

For Right side $X_r=\frac{Force_r}{Area*E}$

Where

Area=L*B*T

$Area=12*10^{-2}*5*10^{-3}$

$Area=6*10^{-4}$

$X_r=2.89855072*10^{-4}$

$X_r=2.89855072*10^{-4}$

Generally the equation for elongation is mathematically given by

$e=strain *12$

For top

$e_t=2.17391304*10^{-4}*12$

$e_t=0.0026$

For Right

$e_r=2.89855072*10^{-4} *12$

$e_r=0.0035$

5 0

3 years ago

Lawn maintenance is an alternative energy source<br> -true<br> -false

Reika [66]

Answer:

false

Explanation:

4 0

3 years ago

The moisture content in air (humidity) is measured by weight and expressed in pounds or ____________________.

VikaD [51]

Moisture content is measured in terms of pounds of water per pound of air (lb water/lb air) or grains of water per pound of air (gr. of water/lb air).

Hope this helps❤

3 0

2 years ago

A shaft made of stainless steel has an outside diameter of 42 mm and a wall thickness of 4 mm. Determine the maximum torque T th

fiasKO [112]

Answer:

Explanation:

Using equation of pure torsion

$\frac{T}{I_{polar} }=\frac{t}{r}$

where

T is the applied Torque

$I_{polar}$ is polar moment of inertia of the shaft

t is the shear stress at a distance r from the center

r is distance from center

For a shaft with

$D_{0} =$ Outer Diameter

$D_{i} =$ Inner Diameter

$I_{polar}=\frac{\pi (D_{o} ^{4}-D_{in} ^{4}) }{32}$

Applying values in the above equation we get

$I_{polar} =\frac{\pi(0.042^{4}-(0.042-.008)^{4})}{32}\\I_{polar}= 1.74$ x $10^{-7} m^{4}$

Thus from the equation of torsion we get

$T=\frac{I_{polar} t}{r}$

Applying values we get

$T=\frac{1.74X10^{-7}X100X10^{6} }{.021}$

T =829.97Nm

7 0

3 years ago

What are some tasks commonly performed in Environmental Service Systems jobs? Check all that apply.

lorasvet [3.4K]

Answer: a,c,d,f

Explanation:

5 0

4 years ago