<h2>
Answer:</h2>
7532V
<h2>
Explanation:</h2>
For a given transformer, the ratio of the number of turns in its primary coil (
) to the number of turns in its secondary coil (
) is equal to the ratio of the input voltage (
) to the output voltage (
) of the transformer. i.e
=
----------------(i)
<em>From the question;</em>
= number of turns in the primary coil = 8 turns
= number of turns in the secondary coil = 515 turns
= input voltage = 117V
<em>Substitute these values into equation (i) as follows;</em>
= 
<em>Solve for </em>
<em>;</em>
= 117 x 515 / 8
= 7532V
Therefore, the output voltage (in V) of the transformer is 7532
1(A)
2(B)
3(E)
4(C)
5(D)
6(B)
7(C)
Answer:
a) 75%
b) 82%
Explanation:
Assumptions:
Properties: The density of water
Conversions:
Analysis:
Note that the bottom of the lake is the reference level. The potential energy of water at the surface becomes gh. Consider that kinetic energy of water at the lake surface & the turbine exit is negligible and the pressure at both locations is the atmospheric pressure and change in the mechanical energy of water between lake surface & turbine exit are:
Then;
gh = 0.491 kJ/kg
= 1559 kW
Therefore; the overall efficiency is:
= 0.75
= 75%
b) mechanical efficiency of the turbine:
thus;
![\eta_{turbine} = \dfrac{\eta_{[turbine- generator]} }{\eta_{generator}} \\ \\ \eta_{turbine} = \dfrac{0.75}{0.92} \\ \\ \eta_{turbine} = 0.82 \\ \\ \eta_{turbine} = 82\%](https://tex.z-dn.net/?f=%5Ceta_%7Bturbine%7D%20%3D%20%5Cdfrac%7B%5Ceta_%7B%5Bturbine-%20generator%5D%7D%20%7D%7B%5Ceta_%7Bgenerator%7D%7D%20%5C%5C%20%5C%5C%20%5Ceta_%7Bturbine%7D%20%3D%20%5Cdfrac%7B0.75%7D%7B0.92%7D%20%5C%5C%20%5C%5C%20%5Ceta_%7Bturbine%7D%20%3D%200.82%20%5C%5C%20%5C%5C%20%5Ceta_%7Bturbine%7D%20%3D%2082%5C%25)
Answer:
Negative peer pressure and High-pressure expectations might be your answer.
Hope this helps :)