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Temka [501]
3 years ago
7

If you are trying to land the plane, which part(s) would you move? How would you move it/them?

Engineering
1 answer:
KiRa [710]3 years ago
7 0

Answer: hope it helps

Explanation:Moving air has a force that will lift kites and balloons up and down. Air is a mixture ... Here is a simple computer simulation that you can use to explore how wings make lift. ... All these dimensions together combine to control the flight of the plane. A pilot ... When the rudder is turned to one side, the airplane moves left or right.

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Technician a s ays a shorted circuit can generate excessive heat. technician b says a shorted circuit will cause the circuit pro
Lerok [7]

Based on the information provided, the technician who is correct is: C. Both Technician A and Technician B.

<h3>What is an open circuit?</h3>

An open circuit can be defined as a type of electric circuit in which the continuity between the conducting wire (paths) has been broken or cut.

This ultimately implies that, an open circuit is designed and developed to prevent the flow of electric charges (electrons or currents) from one point in an electric circuit to another.

In Electrical engineering, a short usually causes an electric circuit protection device such as a fuse, circuit breaker, etc., to open when higher than normal current flows through the electrical circuit.

Read more on short circuit here: brainly.com/question/25018411

#SPJ1

Complete Question:

Technician A says a shorted circuit can generate excessive heat. Technician B says a shorted circuit will cause the circuit protection device to open. who is correct?

A. Technician A only

B. Technician B only

C. Both Technician A and B

D. Neither Technician A nor B

5 0
1 year ago
The smallest crystal lattice defects is a) cracks b) point defects c) planar defects d) dislocations.
ss7ja [257]

Answer:b) Point defects

Explanation: The point defect is the tiny defect that occurs in the lattice. It usually occurs when there is the atoms or ions missing in the lattice structure that creates a irregularity in the structure.The name point defect itself describes that the occurring defect is having a size of point thus is the smallest defect. Therefore option(b) is the correct option.

8 0
3 years ago
According to information found in an old hydraulies book, the energy loss per unit weight of fluid flowing through a nozzle conn
nekit [7.7K]

Answer:

Yes equation is valid.

Explanation:

Given:

h = (0.04 to 0.09)(D/d)^4*V^2/2*g

Using SI units to assign dimensions to every quantity as follows:

Energy loss per unit weight h = J / N = kg m ^2 s^-2 / kg m s^-2 = [m]

Hose diameter D = [m]

Nozzle tip diameter d = [m]

Fluid velocity in the hose V = [ m s^-1 ]

Acceleration of gravity g = [ m s^-2 ]

Using the Given Equation and plug the SI units of respective quantities:

h = (0.04 to 0.09)(D/d)^4*V^2/2*g

[m] = (0.04 to 0.09)([m] / [m])^4*[ m s^-1 ]^2/2*[ m s^-2 ]

Simplify the equation above:

[m] = ( 1 )^4 * [ m^2 s^-2 ] / [ m s^-2 ]

[m] = [m]

Hence, SI units of RHS of given equation = LHS of given equation, we can say the equation has consistent dimensions.

3 0
3 years ago
A closed, rigid tank is lled with a gas modeled as an ideal gas, initially at 27°C and a gage pressure of 300 kPa. The gas is he
sergejj [24]

Answer:

T₂ =93.77  °C

Explanation:

Initial temperature ,T₁ =27°C= 273 +27 = 300 K

We know that

Absolute pressure = Gauge pressure + Atmospheric pressure

Initial pressure ,P₁ = 300+1=301 kPa

Final pressure  ,P₂= 367+1 = 368  kPa

Lets take  temperature=T₂

We know that ,If the volume of the gas is constant ,then we can say that

\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}

{T_2}=T_1\times \dfrac{P_2}{P_1}

Now by putting the values in the above equation we get

{T_2}=300\times \dfrac{368}{301}\ K

The temperature in  °C

T₂ = 366.77 - 273  °C

T₂ =93.77  °C

8 0
3 years ago
Identify the advantages of using 6 tube passes instead of just 2 of the same diameter in shell-and-tube heat exchanger.What are
liq [111]

Answer:

Please check explanation for answer

Explanation:

Here, we are concerned with stating the advantages and disadvantages  of using a 6 tube passes instead of a 2 tube passes of the same diameter:

<u>Advantages</u>

* By using a 6 tube passes diameter, we are increasing the surface area of the heat transfer surface

* As a result of increasing the heat transfer surface area, the rate of heat transfer automatically increases too

            Thus, from the above, we can conclude that the heat transfer rate of a 6 tube passes is higher than that of a 2 tube passes of the same diameter.

<u>Disadvantages</u>

* They are larger in size and in weight when compared to a 2 tube passes of the same diameter and therefore does not find use in applications where space conservation is quite necessary.

* They are more expensive than the 2 tube passes of the same diameter and thus are primarily undesirable in terms of  manufacturing costs

5 0
3 years ago
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