2 years ago

How many atoms of germanium are present in a sample containing 1.65 moles Ge?

Chemistry

1 answer:

otez555 [7]2 years ago

5 0

Answer:

9.9363 x 10^23 atoms

Explanation:

1.65 x Avagadro's Number

1.65 * 6.022 x 10^23 =

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The formula for percent by volume is

$\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%$

If you have 250 mL of a solution that is 2 % v/v,

$\begin{array}{rcl}2 \, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\2 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{2 \times 250\text{ mL}}{100}\\\\ & = & \textbf{5 mL}\\\end{array}$

If there is no change of volume on mixing,

Volume of solution = 250 mL

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Volume of solvent = 245 mL

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