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aniked [119]
2 years ago
13

How many atoms of germanium are present in a sample containing 1.65 moles Ge?

Chemistry
1 answer:
otez555 [7]2 years ago
5 0

Answer:

9.9363 x 10^23  atoms

Explanation:

1.65   x   Avagadro's Number

1.65 * 6.022 x 10^23 =

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Yes, Yes it does in fact
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3 years ago
Mole fraction of the solute in a 1.00. What is the molal aqueous eqaution?
Troyanec [42]
Mole fraction is expressed as the number of moles of solute over the total number of moles of solute and the number of moles of solvent. When expressed in molal, this is equal to number of moles of solute per liter solvent. If the mole fraction is 1.00, this means, all that is in the solution is solute. Hence the molal equivalent is 1.00 too
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3 years ago
In addition to those in Table 14.3, other less stable nitrogen oxides exist. Draw a Lewis structure for each of the following:(c
Natalka [10]

Lewis structure for each of the following N₂O₃ with no N¬N bond is attached below.

Even though pi symmetry occupies the antibonding orbitals of NO, this is unimportant after the dimer forms. A sigma connection exists. The enthalpy of the newly formed sigma bond in the dimer is low because the loss of a particularly distinctive set of single-electron resonance forms that were available for no monomer offset the net gain in bond. When the whole free energy is taken into account, there is no gain because the entropic effects are on the order of 1030kJ/mol, and dimerization is entropically disfavored at G=17kJ/mol. Therefore, any little increase in enthalpy is cancelled out by the loss of entropy.

Learn more about dimer here-

brainly.com/question/17152685

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5 0
2 years ago
Na + O2 → Na2O2<br> Can you guys help me !
vfiekz [6]

Answer:

Explanation:

Assuming that you are asking for the full-balanced equations...

2Na + O2 = Na2O2

H2 + O2 = H2O2; This equation is already balanced, there is no need for change.  

Please let me know if this is not the answer you are looking for and I will amend the answer.

6 0
3 years ago
Octane has a density of 0.692 g/ml at 20oc. how many grams of o2 are required to burn 15.0 gal of c8h18 (the average capacity of
Hatshy [7]

Octane has a density of 0.692 g/ml at 20°C. Grams of O₂ required to burn 15.0 gal of C₈H₁₈ is 1.37868×10⁵g.

Octane is a hydrocarbon having eight carbon atoms and have single bonds only.

Given,

Density of octane = 0.692g/ml

Temperature = 20°C = 293K

Amount of Octane present = 15gal

Molar mass of octane = 114g

We know that,

1 gal = 3.78541L = 3785.4ml

Hence, 15 gal = 56781 ml

Now let's calculate the Mass of octane required:

Mass of octane = 0.692 x 56781

Mass of octane = 39292.45 g

According to the given equation,

C₈H₁₈ + 12.5O₂ ---------> 8CO₂ + 9H₂O

Also, 114g of octane needs-------> 400g of oxygen

39292.45g of octane needs ---------> 137868.24g of oxygen

Hence, oxygen needed to burn octane is 1.37868×10⁵g

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

4 0
2 years ago
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