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goldenfox [79]
3 years ago
12

A rule of thumb in baking is that 1/2 teaspoon of baking soda is neutralized by one cup of sour milk. the acid component in sour

milk is lactic acid, ch3ch(oh)cooh. write the ionic equation for this neutralization reaction.
Chemistry
1 answer:
Sophie [7]3 years ago
3 0

Answer : The ionic equation will be:

CH_3CH(OH)COO^-(aq)+H^+(aq)+Na^+(aq)+HCO_3^-(aq)\rightarrow CH_3CH(OH)COO^-(aq)+Na^+(aq)+H_2O(l)+CO_2(g)

Explanation :

Neutralization reaction : It is a type of chemical reaction in which an acid react with a base to give salt and water as a product that means it reacts to give a neutral solution.

When baking soda (sodium hydrogen carbonate) base react with lactic acid then it react to gives sodium lactate, carbon dioxide and water as a product.

The balanced chemical reaction will be:

CH_3CH(OH)COOH(aq)+NaHCO_3(aq)\rightarrow CH_3CH(OH)COONa(aq)+H_2O(l)+CO_2(g)

The ionic equation will be:

CH_3CH(OH)COO^-(aq)+H^+(aq)+Na^+(aq)+HCO_3^-(aq)\rightarrow CH_3CH(OH)COO^-(aq)+Na^+(aq)+H_2O(l)+CO_2(g)

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In AlCl₃, 3 electrons are being shared by each aluminum atom and 1 electron is being shared by each Cl atom

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6 0
3 years ago
if you can’t already tell by the amount of questions i do not understand chemistry lol, giving brainliest
Vladimir [108]

Answer:

Ok, so the process here is to convert the mass of H2 (hydrogen gas) to moles by dividing the mass by the molar mass of H2. Once you have the moles then you have to multiply by the STP (standard temperature and pressure) molar volume which should be 22.4.

Molar mass of H2 = (1.01)x2 = 2.02g/mol

19.3/2.02 = 9.55 moles

Now just multiply the moles by the molar volume

9.55 moles x 22.4 = 213.92 Litres of H2 are in 19.3g of H2

6 0
3 years ago
Consider the formation of ammonia in two experiments. (a) to a 1.00-l container at 727°c, 1.30 mol of n2 and 1.65 mol of h2 are
emmasim [6.3K]
When it comes to equilibrium reactions, it useful to do ICE analysis. ICE stands for Initial-Change-Equilibrium. You subtract the initial and change to determine the equilibrium amounts which is the basis for Kc. Kc is the equilibrium constant of concentration which is just the ratio of products to reactant. 

Let's do the ICE analysis

      2 NH₃ ⇄ N₂ + 3 H₂
I         0        1.3    1.65
C     +2x       -x      -3x
-------------------------------------
E       0.1        ?        ?

The variable x is the amount of moles of the substances that reacted. You apply the stoichiometric coefficients by multiplying it by x. Now, we can solve x by:

Equilibrium NH₃ = 0.1 = 0 + 2x
x = 0.05 mol
Therefore,
Equilibrium H₂ = 1.65 - 3(0.05) = 1.5 mol
Equilibrium N₂ = 1..3 - 0.05 = 1.25 mol

For the second part, I am confused with the given reaction because the stoichiometric coefficients do not balance which violates the law of conservation of mass. But you should remember that the Kc values might differ because of the stoichiometric coefficient. For a reaction: aA + bB ⇄ cC, the Kc for this is

K_{C} = \frac{[ C^{c} ]}{[ A^{a} ][ B^{b} ]}

Hence, Kc could vary depending on the stoichiometric coefficients of the reaction.
8 0
3 years ago
oth hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you opene
Ksju [112]

Answer: Odor of ammonia would we detect first on the other side of the room.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{M_{NH_3}}{M_{H_2S}}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{17.031}{34.1}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=0.71

Thus the odor of ammonia would we detect first on the other side of the room as the rate of effusion of ammonia would be faster as it has low molecular weight as compared to hydrogen sulphide.

5 0
3 years ago
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KIM [24]
Yes, I hope this helped
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3 years ago
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