I think it should be option (b)
Answer: The observer must walk 0.2897m towards either speaker.
Explanation:
Let us make distance between the two speakers to be =D
frequency emitted by the two speakers in phase=f
v= speed of sound, 343 m/s
λ=wavelength
---- solving for λ, wavelength, using the equation λ=v/f. 343/296
= 1.15878m
Also destructive interference is given as
⎮d1-d2⎮=λ/2
Because the observer should be able to walk far enough to make the distance to one speaker differ from the distance to the other speaker by ½ wavelength.
This will give us
d1-d2= 1.15878 /2
d1-d2=0.5794m
For the distance moved on either side, we have D/2
Therefore 0.5794/2=distance to move on either side. Giving us
0.2897m
In conclusion, This means that the observer has to walk so as to be 0.5794m closer to one speaker from another; this means walking 0.2897m towards either speaker.
You did not provide the options. However, the options are
I = 6.0, R= 4.0 ohms
I = 9.0, R= 2.0ohms
I = 3.0, R= 2.0ohms
I = 8.0, R= 8.0 ohms
Answer:
The order of the resistors from the highest to the lowest is:
I = 8.0, R= 8.0 ohms
I = 6.0, R= 4.0 ohms
I = 9.0, R= 2.0ohms
I = 3.0, R= 2.0 ohms
Explanation:
ohm's law states that voltage across a conductor is directly proportional to the current flowing through it. V = IR
Based on this formula, the voltages in each of the resistors are calculated below from the highest to the lowest
V = 8 * 8 =64 volts
V = 6 * 4 =24 volts
V = 9 * 2 =18 volts
V = 3 * 2 =6 volts
Answer:i f I understand your question correctly, the formula is as follows:
Note: The sign convention is based on distances which are measured from the lens to the object or image of regard. Distances measured in the same direction the light is moving are positive and distances measured in the opposite direction the light is moving are negative.
The measurements are in meters
The “ambient” index of refraction is assumed to be n=1.00
The inverse of the object distance plus the dioptric power of the lens (convex—positive and concave—negative) equals the inverse of the image distance.
Or 1/Od +Dl =1/Id
Please note, it has been a long time since I thought about teaching this concept to students.
<h3>Hope this helps have a awesome day/night❤️✨</h3>
Explanation: