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fredd [130]
3 years ago
9

SUBMIT

Chemistry
1 answer:
shutvik [7]3 years ago
6 0

Answer:

i guess its the red wave so A

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ASAP (:
Korvikt [17]

1) CO (g) + 2H_{2}(g) ---> CH_{3}OH (g)

Moles of methanol = 208 kg CH_{3}OH * \frac{1000 g}{1 kg} * \frac{1 mol CH_{3}OH}{32.04 g CH_{3}OH} = 6492 mol CH_{3}OH

Mass of H_{2} that would produce 208 kg methanol =

6492 mol CH_{3}OH * \frac{2 mol H_{2}}{1 mol CH_{3}OH} * \frac{2.02 g H_{2}}{1 mol H_{2}} * \frac{1 kg}{1000 g}=  26.2 kg H_{2}

2) Mass of sodium = 1.3 * 10^{21} atoms Na * \frac{1 mol Na}{6.022* 10^{23}atoms Na} * \frac{22.99 g Na}{1 mol Na} = 0.0496 g Na

3) Mass of mercury = 1.2 mL * 13.6 \frac{g}{mL} = 16.32 g

Number of atoms of mercury = 16.32 g Hg * \frac{1 mol Hg}{200.59 g Hg} * \frac{6.022* 10^{23} atoms Hg}{1 mol Hg} =   4.9 * 10^{22} atoms Hg

5 0
3 years ago
Please show all of your work! :)
Paladinen [302]

Answer:

A

Explanation:

To answer this, we need to use Gay-Lussac's law, which states that:

\frac{P_1}{T_1}= \frac{P_2}{T_2} , where P is pressure and T is temperature

The initial pressure we're given is 4.5 atm (so P1 = 4.5) and the temperature is 45.0°C; however, we need to change Celsius to Kelvins, so add 273 to 45.0: 45.0 + 273 = 318 K (so T1 = 318).

The final pressure is what we want to find, but we do know the final temperature is 3.1°C. Converting this to Kelvins, we get: 3.1 + 273 = 276.1 K, which means T2 = 276.1.

Plug these values in:

\frac{P_1}{T_1}= \frac{P_2}{T_2}

\frac{4.5}{318}= \frac{P_2}{276.1}

Multiply both sides by 276.1:

P_2 ≈ 3.9 atm

The answer is thus A.

3 0
2 years ago
Calculate the mass fraction of sodium chloride in the solution if 20 g of it is dissolved in 300 ml of water.
MA_775_DIABLO [31]

The mass fraction of sodium chloride is 0.0625

<h3>What is the mass fraction of sodium chloride in the solution?</h3>

The mass fraction of sodium chloride is the ratio of the mass of sodium chloride to the total mass of the solution.

The mass fraction of sodium chloride is determined as follows;

mass of sodium chloride = 20 g

  • mass of water = volume * density

density of water = 1 g/mL

volume of water = 300 mL

mass of water = 300 mL * 1 g/mL

mass of water = 300 g

total mass of solution = 20 + 300 = 320 g

mass fraction of sodium chloride = 20/320

mass fraction of sodium chloride = 0.0625

Learn more about mass fraction at: brainly.com/question/14783710

#SPJ1

5 0
1 year ago
The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v).
vovangra [49]

Answer:

Density is an intensive property

Explanation:

The intensive properties don´t depend on mass or size, if you have a liter of water, this litter have a density equal 1000 kg/m^3. If zo have 250 liters of water, the density is 1000 kg/m^3 too.

The density does not change with the addition or substraction of matter.

I hope I have been clear.

8 0
3 years ago
Read 2 more answers
A gas has a volume of 340.0 mL at 45.90 oC. What is the new temperature of the gas, in Kelvin, if the volume increased to 550.0
d1i1m1o1n [39]

Answer:

Solution for A gas has a volume of 340.0 mL at 45.90 degree celsius. What is the new temperature of the gas, in kelvin, if the volume increased to 550.0 mL.

Missing: oC. ‎| Must include: oC.

Explanation:

6 0
2 years ago
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