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Spaceship 1 and spaceship 2 have equal masses of 300 kg. spaceship 1 has a speed of 0 m/s, and spaceship 2 has a speed of 6 m/s.
1 answer:
The final speed is 3 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, in absence of external forces, the total momentum of the two spaceships must be conserved. So we can write:
where
is the mass of each spaceship
is the initial velocity of spaceship 1
is the initial velocity of spaceship 2
v is the combined velocity of the two spaceships after the collision
Solving for v, we find
So, their final speed is 3 m/s.
Learn more about conservation of momentum:
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Answer:
- The specific mechanical energy of the air in the specific location is 40.5 J/kg.
- The power generation potential of the wind turbine at such place is of 2290 kW
- The actual electric power generation is 687 kW
Explanation:
- The mechanical energy of the air per unit mass is the specific kinetic energy of the air that is calculated using:
where V is the velocity of the air.
- The specific kinetic energy would be:
.
- The power generation of the wind turbine would be obtained from the product of the mechanical energy of the air times the mass flow that moves the turbine.
- To calculate mass flow it is required first to calculate the volumetric flow. To calculate the volumetric flow the next expression would be:
- Then the mass flow is obtain from the volumetric flow times the density of the air:
- Then, the Power generation potential is:
- The actual electric power generation is calculated using the definition of efficiency:
, where η is the efficiency,
is the energy actually produced and,
is the energy input. Then solving for the energy produced: