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alina1380 [7]
2 years ago
10

I NEED HELP ASAP! Compare the spectrum of the unknown gas collected at the bulb company

Physics
1 answer:
Maru [420]2 years ago
4 0

The leaking gas is Neon.

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<em>Your question is not complete, kindly check the image uploaded for the remaining part of the question.</em>

The gases commonly used in fluorescent light bulbs include Hydrogen, Helium, Neon, Argon, Krypton, Xenon.

Fluorescent lamps emit light of wavelength between 400 nm to 700 nm.

In the given chart the suspected gases in the bulb include;

Hydrogen (H), maximum wavelength (nm) = 410, 434, 86, 656

Helium (He), maximum wavelength, (nm) = 438, 443, 7, 471, 42, 501, 50, 587, 66.

Neon, (Ne), maximum wavelength, (nm) = 421, 423, 425, 436,

The leaking gas is determined as follows;

  • For hydrogen the maximum wavelength fluctuated between 86 and 656, which caused the average of the maximum wavelength to be 396.5 nm. The average of the maximum wavelength is below the minimum wavelength of the Fluorescent lamp.
  • For Helium, the maximum wavelength fluctuated between 7 and 587, which caused the average of the maximum wavelength to be 282.11 nm. The average of the maximum wavelength is below the minimum wavelength of the Fluorescent lamp.
  • For Neon (Ne), the maximum wavelength is fairly constant and the average of the maximum wavelength is 426.25 nm. This value is above the minimum wavelength of the fluorescent lamps.

Thus, the leaking gas is Neon.

Learn more here: brainly.com/question/7388951

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A hungry 169169 kg lion running northward at 77.377.3 km/hr attacks and holds onto a 31.731.7 kg Thomson's gazelle running eastw
navik [9.2K]

Answer:  75,242.9 m/s

Explanation:

from the question we are given the following parameters

mass of Lion (ML) = 169,169 kg

velocity of lion (VL) = 777,377.7 m/s

mass of Gazelle (Mg) = 31,731.7 kg

velocity of Gazelle (Vg) = 63,863.8 kg

mass of Lion and Gazelle (M) = 200,900.7 kg

velocity of Lion and Gazelle (V) = ?

The first figure below shows the motion of the Lion and Gazelle with their direction.

The second diagram shows the motion of the Lion and Gazelle with their directions rearranged to form a right angle triangle.

from the triangle formed we can get the velocity of the Lion and Gazelle immediately after collision using their momentum and Phytaghoras theorem

momentum = mass x velocity

momentum of the Lion = 169,169 x 77,377.3 = 13,089,840,463.7 kgm/s

momentum of the Gazelle = 31,731.7 x 63,863.8 = 2,026,506,942.46 kgm/s

momentum of the Lion and Gazelle = 200,900.7  x V

now applying Phytaghoras theorem we have

13,089,840,463.7 + 2,026,506,942.46 =  200,900.7 x V

15,116,347,406.16 = 200,900.7 x V

V = 75,242.9 m/s

7 0
2 years ago
Read 2 more answers
Due today HELP HELP HELP
Anna [14]

Vas happenin!

Independent variable : amount of water each day

Dependent variable: water on the windsill

Hypotheses: Ben wants to try by adding water each day to two different places. Will that work? Will that effect the water?


Hope this helps you out

*smiles*


-Zayn Malik
5 0
2 years ago
If Anisa swims 85.4 yards in five minutes, how many meters will she swim in 70.0 seconds? ( use the metric system for this quest
Ira Lisetskai [31]

Answer : 18.22 meters

Explanation:

1 yard. = 0.9144 meters

85.4 yards = 78.08976 meters

1 minute = 60 seconds

5 minutes = 300 seconds

Speed of Anisa = distance / time

Speed of Anisa = 78.08976 meters / 300 seconds

Speed of Anisa = 0.26029 meters / second.

Distance travelled in 70 seconds = speed * 70

Distance travelled in 70 seconds = 0.26029 * 70 = 18.22 meters

8 0
2 years ago
Please do all of i will give you brainlest and thanks to best answer
vlabodo [156]

Answer:the answer is A

Explanation:

3 0
3 years ago
The operating temperature of a tungsten filament in an incandescent light bulb is 2450 K, and its emissivity is 0.350. Find the
natulia [17]

Answer:

The value is   A =  2.80 *10^{-4} \  m^2

Explanation:

From the question we are told that

The  operating temperature is  T  =  2450 \  K

The emissivity is  e =  0.350

 The  power rating is  P  =  200 \  W

Generally the area is mathematically represented as

      A = \frac{P}{ e *  \sigma  *  T^2}

Where  \sigma is the Stefan Boltzmann constant  with value  

      \sigma  =  5.67 *10^{-8} \  W/m^2\cdot K^4

So

     A =  \frac{200}{0.350 *  5.67*10^{-8} *  2450^{4}}

     A =  2.80 *10^{-4} \  m^2

8 0
3 years ago
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