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alina1380 [7]
3 years ago
10

I NEED HELP ASAP! Compare the spectrum of the unknown gas collected at the bulb company

Physics
1 answer:
Maru [420]3 years ago
4 0

The leaking gas is Neon.

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<em>Your question is not complete, kindly check the image uploaded for the remaining part of the question.</em>

The gases commonly used in fluorescent light bulbs include Hydrogen, Helium, Neon, Argon, Krypton, Xenon.

Fluorescent lamps emit light of wavelength between 400 nm to 700 nm.

In the given chart the suspected gases in the bulb include;

Hydrogen (H), maximum wavelength (nm) = 410, 434, 86, 656

Helium (He), maximum wavelength, (nm) = 438, 443, 7, 471, 42, 501, 50, 587, 66.

Neon, (Ne), maximum wavelength, (nm) = 421, 423, 425, 436,

The leaking gas is determined as follows;

  • For hydrogen the maximum wavelength fluctuated between 86 and 656, which caused the average of the maximum wavelength to be 396.5 nm. The average of the maximum wavelength is below the minimum wavelength of the Fluorescent lamp.
  • For Helium, the maximum wavelength fluctuated between 7 and 587, which caused the average of the maximum wavelength to be 282.11 nm. The average of the maximum wavelength is below the minimum wavelength of the Fluorescent lamp.
  • For Neon (Ne), the maximum wavelength is fairly constant and the average of the maximum wavelength is 426.25 nm. This value is above the minimum wavelength of the fluorescent lamps.

Thus, the leaking gas is Neon.

Learn more here: brainly.com/question/7388951

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A ball of mass 0.120 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.820 m. W
Vikentia [17]

Answer:

1.0752 kgm/s

Explanation:

Considering when the drop was dropped from rest from a height,

mass of the ball, m = 0.120 kg

height, h = - 1.25 m

the initial velocity, u = 0 m/s

the acceleration due to gravity, g = - 9.8 m/s²

From equation of motion

                            V^{2} = U^{2} + 2gh

Substituting the values,

                             V^{2} = 0^{2} + 2(-9.8 m/s^{2})(-1.25 m)

                             V^{2} = 24.5 m/s

                             V = \sqrt{24.5} \ m/s

                             V = 4.95 \ m/s

                            V = ± 4.95 m/s

                            V = - 4.95 m/s

Since the ball is moving downward, the final velocity of the ball when it hits the floor is  V = - 4.95 m/s  

Considering when the ball rebounds from the floor,

assume the mass of the ball still remain, m = 0.120 kg

height, h = 0.820 m

the final velocity, v = 0 m/s  

the acceleration due to gravity, g = - 9.8 m/s²

From equation of motion

                            V^{2} = U^{2} + 2gh

Substituting the values,

                            0^{2} = U^{2} + 2(-9.8 m/s^{2})(0.820 m)

                            0 = U^{2} - 16.072 m/s

                            U^{2} = 16.072 m/s

                            U = \sqrt{16.072} \ m/s

                           U = ± 4.01 m/s

                          U = + 4.01 m/s

Since the ball is moving upward, the initial velocity of the ball from the bounce from the floor is  U = + 4.01 m/s                        

From Newton's second law of motion, applied force is directly proportional to the rate of change in momentum.

                            F = \frac{mv - mu}{t}

                          F.t = m(v - u)

       ⇒      Impulse = Change in momentum

To calculate the impulse, the moment before the ball hits the ground will be the initial momentum while the moment the ball rebounces will be the final velocity,                        

          ∴          F.t = 0.120  kg(4.01  m/s - (-4.95  m/s) )

                      F.t = 0.120  kg(4.01  m/s + 4.95  m/s) )

                      F.t = 0.120  kg × 8.96  m/s

                      Impulse  = 1.0752 kgm/s

The impulse given to the ball by the floor is 1.0752 kgm/s

                             

6 0
3 years ago
I will fan and give 2 medals!!!!!!
Maksim231197 [3]
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<span>I.                  </span>Rare gaseous envelope

<span>II.              </span>Irregular pearly glow

<span>III.          </span>Total solar eclipse

<span>IV.             </span>Surrounds darkened moon

<span>V.                 </span>Caused by diffraction

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<span>I.                  </span>loop shape

<span>II.              </span>large bright gaseous

<span>III.          </span>luminous hydrogen gas

<span>IV.             </span>rises above chromospheres

<span>V.                 </span>anchored to surface (sun’s surface)

<span> Solar Flare </span>

<span>I.                  </span>Intense High-energy

<span>II.              </span>Causes electromagnetic disruptions

<span>III.          </span>In solar atmosphere

<span>IV.             </span>Varies in brightness

<span>V.                 </span>Emits radiation 

<span> Sunspots </span>

<span>I.                  </span>Surface dark spots

<span>II.              </span>Strong magnetic fields

<span>III.          </span>Solar magnetic storms

<span>IV.             </span> Visible through telescope 

<span>V.                 </span>Cooler than photospheres

I did this in class I got 100%

7 0
3 years ago
Drag the titles to the correct boxes to complete the pairs.
PilotLPTM [1.2K]
Can you input a picture??
5 0
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Please help! you are amazing! brainliest too!
german
I think it’s B hope it helps:)
6 0
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What is the meaning of physics​
Valentin [98]

Answer:

the branch of science concerned with the nature and properties of matter and energy

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