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djyliett [7]
3 years ago
14

A 1000 kg racecar, which is capable of a top speed of 125 m/s, is sitting in a

Physics
1 answer:
k0ka [10]3 years ago
5 0
Sitting = no movement
KE=0
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An airplane is flying in a horizontal circle at a speed of 100 m/s. The 80.0 kg pilot does not want the centripetal acceleration
Tema [17]

Answer:

The force will be "5,488". A further solution is provided below.

Explanation:

The given values are:

speed,

v = 100m/s

mass,

m = 80 kg

acceleration,

a = 7

Now,

Radius will be:

⇒ r=\frac{v^2}{ac}

⇒    =\frac{(100)^2}{7\times 9.8}

⇒    =\frac{10000}{68.6}

⇒    =145.77

Force will be:

⇒ F=m\times ac

⇒     =80\times 68.6

⇒     =5488

3 0
2 years ago
Im done with this XD im giving away my points XD<br><br> what comes up must go down who said that?
Gnom [1K]
Your answer is <span>Isaac Newton. Hope this helps.</span>
7 0
3 years ago
Read 2 more answers
A compact disc (CD) stores music in a coded pattern of tiny pits 10⁻⁷m deep. The pits are arranged in a track that spirals outwa
Serggg [28]

a) Angular speed of the innermost part: 50 rad/s, outermost part: 21.6 rad/s

b) The length of the track would be 5,550 m

c) The average angular acceleration is -6.4\cdot 10^{-3}rad/s

Explanation:

a)

For an object in uniform circular motion, the relationship between angular speed and linear speed is

v=\omega r

where

v is the linear speed

\omega is the angular speed

r is the radius of the circle

Here the linear speed of the track is constant:

v = 1.25 m/s

For the innermost part of the disk,

r = 25.0 mm = 0.025 m

So the angular speed is

\omega_i = \frac{v}{r_i}=\frac{1.25}{0.025}=50 rad/s

For the outermost part,

r = 58.0 mm = 0.058 m

So the angular speed is

\omega_o = \frac{v}{r_o}=\frac{1.25}{0.058}=21.6 rad/s

b)

The maximum playing time of the disk is

t=74.0 min \cdot (60 s/min)=4440 s

If the track was stretched out in a straight line, the motion of the track would be a uniform motion (since it is moving at constant speed), so we can use the equation

v=dt

where

v is the linear speed

d is the length coverted in a straight line

t is the time

Substituting v = 1.25 m/s and solving for d,

d=vt=(1.25)(4440)=5550 m

c)

The angular acceleration is given by

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_f is the final angular speed

\omega_i is the initial angular speed

t is the time

A CD is read from the innermost part to the outermost part, so we have:

\omega_i = 50 rad/s (at the innermost part)

\omega_f = 21.6 rad/s (at the outermost part)

t = 74.0 min = 4440 s is the time

Substituting, the average angular acceleration is

\alpha = \frac{21.6-50.0}{4440}=-6.4\cdot 10^{-3}rad/s

where the negative sign means the CD is decelerating.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0
2 years ago
Why did the magnitude of the doppler shift increase as the velocity of the sound source increased?
jolli1 [7]
The Doppler effect happens as the result of a source of waves having relative motion to observers somewhere else consider that if something is producing a wave of wavelength W and it is moving relative to the waves then as the waves spread out it seems to chase one side and run away from the other side there for wavelengths produced on the scale it is chasing will be less than W on the side it is running away from the apparent wavelength will be greater than W so using this knowledge if the source of the Waves moves faster than it will chase one of the more closely and run away from the other more quickly there for making the short wavelength even shorter and the long wavelength even longer can turn you in and tell you have gone all over the speed of wave creating boom when dealing with sound this is what causes a sonic boom this lengthening of the long wavelengths and the shortening of the short wavelengths is referred to as being a greater Doppler shift
6 0
3 years ago
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Alexandra knows that the atomic number of the element potassium, K, is 19. She also knows that one particular isotope of potassi
fiasKO [112]
I believe the answer is 58 but I’m not sure
8 0
3 years ago
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