Answer:
5,760,000 lb-ft²/s²
Explanation:
Work done, W = mgy where m = mass of stone = 12,000 lb, g = 32 ft/s² and y = vertical distance = 15 ft.
So, W = mgy = 12,000 lb × 32 ft/s² × 15 ft. = 5,760,000 lb-ft²/s²
Explanation:
I don't understand this question
could you please explain
Answer:
v = 8.96 m/s
Explanation:
Initial speed of the ball, u = 10 m/s
It caught 1 meter above its initial position.
Acceleration due to gravity, 
We need to find the final speed of the ball when it is caught. Let is equal to v. To find the value of v, use third equation of motion as :



v = 8.96 m/s
So, the speed of the ball when it is caught is 8.96 m/s. Hence, this is the required solution.
Answer:
F=mass x acceleration
1000= 2000 x a
a=1000/2000
a=1/2 m/sec^2
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