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abruzzese [7]
3 years ago
7

10. The repair order is a legal document because

Engineering
1 answer:
babymother [125]3 years ago
4 0
I think it’s B.) it’s signed by the customer
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In ________ programming, the programming is centered on objects that are created from abstract data types that encapsulate data
Contact [7]

Answer:

<em>Object-oriented</em>

Explanation:

<em>Object Oriented programming</em> <em>(OOP)</em> is a specific way of programming, where the code is organized in units called classes, from which objects are created that are related to each other to achieve the objectives of the applications. Object-oriented programming took over as the dominant programming style in the mid-1980s, largely due to the influence of C ++. Its dominance was consolidated thanks to the rise of graphical user interfaces, for which object-oriented programming is particularly well suited. Its most important characteristics are the following:

  • Encapsulation
  • Polymorphism
  • Abstraction
  • Inheritance

8 0
3 years ago
A copper block receives heat from two different sources: 5 kW from a source at 1500 K and 3 kW from a source at 1000 K. It loses
LUCKY_DIMON [66]

Answer:

a) Zero

b) the rate of entropy generation in the system's universe = ds/dt = 0.2603 KW/K

Explanation:

a) In steady state  

Net rate of Heat transfer = net rate of heat gain -  net rate of heat lost  

Hence, the rate of heat transfer = 0

b) In steady state, entropy generated  

ds/dt = - [ Qgain/Th1 + Qgain/Th2 - Qlost/300 K]

Substituting the given values, we get –  

ds/dt = -[5/1500 + 3/1000 – (5+3)/300]

ds/dt = - [0.0033 + 0.003 -0.2666]

ds/dt = 0.2603 KW/K

 

6 0
3 years ago
A search will start from a visual lead<br> true<br> false
BlackZzzverrR [31]
True

An organized searching process will need to start from the visual lead area. Eye focus and eye movements from the path of travel in an organized pattern describes a visual search process.
4 0
2 years ago
Read 2 more answers
Provide an argument justifying the following claim: The average (as defined here) of two Java ints i and j is representable as a
ahrayia [7]

Answer:

public static int average(int j, int k) {

return (int)(( (long)(i) + (long)(j) ) /2 );

}

Explanation:

The above code returns the average of two integer variables

Line 1 of the code declares a method along with 2 variables

Method declared: average of integer data type

Variables: j and k of type integer, respectively

Line 2 calculates the average of the two variables and returns the value of the average.

The first of two integers to average is j

The second of two integers to average is k

The last parameter ensures average using (j+k)/2

3 0
3 years ago
Your program must output each student’s name in the form: last name followed by a comma, followed by a space, followed by the fi
Reptile [31]

Answer:

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

char getStudentGrade(int testScore);

//Declare constant max students in file 10

const int maxStudents = 10;

struct StudentType

{

  string studentFName;

  string studentLName;

  int testScore;

  char grade;

};

void readStudentData(StudentType students[]){

  int i = 0;

 

  ifstream infile;

  infile.open("inputStudentData.txt");

 

 

  while (!infile.eof())

  {

   infile >> students[i].studentFName;

   infile >> students[i].studentLName;

   infile >> students[i].testScore;

   students[i].grade = getStudentGrade(students[i].testScore);

      i++;

  }

}

char getStudentGrade(int testScore){

  char grade;

  if(testScore >= 80) {

      grade = 'A';      

  }

  else if(testScore >= 60) {

      grade = 'B';

  }

  else if(testScore >= 50) {

      grade = 'C';  

  }

  else if(testScore >= 40) {

      grade = 'D';      

  }

  else {

      grade = 'F';  

  }

  return grade;

}

int main()

{

 

  StudentType students[10];

 

  readStudentData(students);

 

  for(int i=0;i<maxStudents;i++) {

      students[i].grade = getStudentGrade(students[i].testScore);

  }

 

  for(int i=0; i<maxStudents; i++){    

      cout << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

  }

  ofstream outputFile;

  outputFile.open ("outputStudentData.txt");

 

  for(int i=0; i<maxStudents; i++){    

      outputFile << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

  }

  outputFile.close();

  return 0;

}

3 0
4 years ago
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