Answer:
32000 bits/seconds
Explanation:
Given that :
there are 16 signal combinations (states) = 2⁴
bits n = 4
and a baud rate (number of signals/second) = 8000/second
Therefore; the number of bits per seconds can be calculated as follows:
Number of bits per seconds = bits n × number of signal per seconds
Number of bits per seconds = 4 × 8000/second
Number of bits per seconds = 32000 bits/seconds
uniform
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Answer:
The time complexity will be "O(n log n)".
Explanation:
- Many realistic Quick sort implementations choose a randomized special edition. The time complexity variable O(n Logn) was predicted in the randomized edition.
- Throughout the randomized version, probably the most disgusting case is also conceivable, but by far the worst scenario for something like a given pattern does not exist as well as randomized Quick sort performs well throughout the practice.
