10. The repair order is a legal document because

A car engine with a thermal efficiency of 33% drives the air-conditioner unit (a refrigerator) besides powering the car and othe

fgiga [73]

Answer:

The rate of fuel required to drive the air conditioner $Q_h = 6.061 kW$

The flow rate of the cold air is $\r m = 0.30765 kg/s$

Explanation:

From this question we are told that

The efficiency is $\eta = 33$ % = 0.33

Temperature for the hot day is $T_h = 35^oC = 308 K \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (35+273)$

Temperature after cooling is $T_c = 5^oC = 278K$

The input power is $P_{in} = 2kW$

The rate of fuel required to drive the air conditioner can be mathematically represented as

$Q_h = \frac{P_{in}}{\eta}$

$= \frac{2}{0.33} = 6.061 kW$

From the question the air condition is assumed to be half as a Carnot refrigeration unit

This can be Mathematically interpreted in terms of COP(coefficient of performance) as

$\beta_{air} = 0.5 \beta$

where $\beta$ denotes COP and is mathematically represented as

$\beta = \frac{Q_c}{P_{in}}$

= > $Q_c = \beta P_{in}$

Where $Q_c$ is the rate of flue being burned for cold air to flow

Now if the COP of a Carnot refrigerator is having this value

$\beta_{Carnot } = \frac{T_c}{T_h - T_c}$

$= \frac{278}{308-278}$

$\beta_{Carnot} = 9.267\\$

Then

$\beta_{air} = 0.5 * 9.2667$

$= 4.6333$

Now substituting the value of $\beta$ to solve for $Q_c$

$Q_c = \beta P_{in}$

$= 4.6333 *2$

$9.2667kW$

The equation for the rate of fuel being burned for the cold air to flow

$Q_c = \r mc_p \Delta T$

Making the flow rate of the cold air

$\r m = \frac{Q_c}{c_p \Delta T}$

$= \frac{9.2667}{1.004}* (308 - 278)$

$= 0.30765 kg/s$

4 0

3 years ago

4. Calculate the square root of potato using the sqrt() function. Print out the value of potato again to verify that the value o

N76 [4]

Answer:

potato<-100

print(potato)

sqrt(potato)

potato<-potato*2

print(potato)

Explanation:

The complete question is as follows

Create a variable called potato whose value corresponds to the number of potatoes you’ve eaten in the last week. Or something equally ridiculous. Print out the value of potato.

Calculate the square root of potato using the sqrt() function. Print out the value of potato again to verify that the value of potato hasn’t changed.

Reassign the value of potato to potato * 2.

Print out the new value of potato to verify that it has changed

The question was answered using R programming language.

At line 1, I assumed that I ate 100 potatoes in the previous week.

So, potato = 100

At line 2, the value of potato is printed as 100.

At line 3, the square root of potato is calculated using sqrt function: Square for of 100 = 10

At line 4,the initial value of potato is doubled and stored in potato variable. 100 * 2 = 200

At line 5, the new value of potato is printed: 200.

8 0

4 years ago

PLEASE HELP, TEST MULTIPLE CHOICE QUESTIONS

Rina8888 [55]

Answer:

c

Explanation:

dbfjex vadamhqrmtwg

8 0

3 years ago

Read 2 more answers

a torque of 24 ft pounds is the result when a force of ______ pounds is applied to a wrench that is 18 inches long.

andrew-mc [135]

Answer:

16

Explanation:

The product of feet and pounds is the torque. 18 inches is 1.5 feet.

(1.5 ft)(x lbs) = 24 ft·lbs

x lbs = (24 ft·lbs)/(1.5 ft) = 16 lbs

The force will be 16 pounds applied to an 18-inch wrench to obtain 24 ft·lbs.

5 0

3 years ago

Read 2 more answers

Hellpppppppppp will give brainliest just help!!!!!!

aliya0001 [1]

Turbooooooooooi

Hope it helps Mister

3 0

3 years ago