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Arada [10]
3 years ago
6

The motor of an electric vehicle runs at an average of 50 hp for one hour and 25 minutes. Determine the total energy. Write the

result in engineering notation and with SI units.
Engineering
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.

Explanation:

Power is the rate of change of work in time, since given input is average power, the total energy (\Delta E) of the motor of the electric vehicle, measured in joules, is determined by this formula:

\Delta E = \dot W \cdot \Delta t

Where:

\dot W - Average power, measured in watts.

\Delta t - Time, measured in seconds.

Now, let convert average power and time into watts and seconds, respectively:

Average Power

\dot W = (50\,hp)\times \frac{746\,W}{1\,hp}

\dot W = 3.730\times 10^{4}\,W

Time

\Delta t = (1\,h)\times \frac{3600\,s}{1\,h} + (25\,min)\times \frac{60\,s}{1\,min}

\Delta t = 5.100\times 10^{3}\,s

Then, the total energy is:

\Delta E = (3.730\times 10^{4}\,W)\cdot (5.100\times 10^{3}\,s)

\Delta E = 1.902\times 10^{8}\,J

The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.

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Answer:

my_mul:

.globl my_mul

my_mul:

   //Multiply X0 and X1

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   SUB SP, SP, 16       //make room for X19 on the stack

   STUR X19, [SP, 0]    //push X19

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mult_loop:

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mult_eol:

   LDUR X19, [SP, 0]

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Explanation:

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3 years ago
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Explanation:

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Which crystal system(s) listed below has (have) the following relationship for the unit cell edge lengths?
lianna [129]

Answer:

Both B and G ( Hexagonal and Tetragonal )

Explanation:

The crystals system listed below has the following relationship for the unit cell edge lengths; a = b ≠ c ( hexagonal and Tetragonal )

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A 35 ft long solid steel rod is subjected to a load of 8,000 lb. This load causes the rod to stretch 0.266 in. The modulus of el
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A furnace wall is to be built of 20-cm firebrick and building (structural) brick of same thickness. The thermal conductivities o
Norma-Jean [14]

Answer:

q=2313.04W/m^2

T=690.86°C

Explanation:

Given that

Thickness t= 20 cm

Thermal conductivity of firebrick= 1.6 W/m.K

Thermal conductivity of structural brick= 0.7 W/m.K

Inner temperature of firebrick=980°C

Outer temperature of structural brick =30°C

We know that thermal resistance

R=\dfrac{t}{KA}

These are connect in series

R=\left(\dfrac{t}{KA}\right)_{fire}+\left(\dfrac{t}{KA}\right)_{struc}

R=\dfrac{0.2}{1.6A}+\dfrac{0.2}{0.7A}\ K/W

R=\dfrac{23}{56A}\ K/W

Heat transfer

Q=\dfrac{\Delta T}{R}

Q=56A\times \dfrac{980-30}{23}\ W

So heat flux

q=2313.04W/m^2

Lets temperature between interface is T

Now by equating heat in both bricks

\dfrac{980-T}{\dfrac{0.2}{1.6A}}=\dfrac{T-30}{\dfrac{0.2}{0.7A}}

So T=690.86°C

6 0
3 years ago
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