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Arada [10]
4 years ago
6

The motor of an electric vehicle runs at an average of 50 hp for one hour and 25 minutes. Determine the total energy. Write the

result in engineering notation and with SI units.
Engineering
1 answer:
Sunny_sXe [5.5K]4 years ago
6 0

Answer:

The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.

Explanation:

Power is the rate of change of work in time, since given input is average power, the total energy (\Delta E) of the motor of the electric vehicle, measured in joules, is determined by this formula:

\Delta E = \dot W \cdot \Delta t

Where:

\dot W - Average power, measured in watts.

\Delta t - Time, measured in seconds.

Now, let convert average power and time into watts and seconds, respectively:

Average Power

\dot W = (50\,hp)\times \frac{746\,W}{1\,hp}

\dot W = 3.730\times 10^{4}\,W

Time

\Delta t = (1\,h)\times \frac{3600\,s}{1\,h} + (25\,min)\times \frac{60\,s}{1\,min}

\Delta t = 5.100\times 10^{3}\,s

Then, the total energy is:

\Delta E = (3.730\times 10^{4}\,W)\cdot (5.100\times 10^{3}\,s)

\Delta E = 1.902\times 10^{8}\,J

The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.

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A 4-stroke Diesel engine with a displacement of Vd = 2.5x10^-3m^3 produces a mean effective pressure of 6.4 bar at the speed of
yKpoI14uk [10]

Answer:

The power developed by engine is 167.55 KW

Explanation:

Given that

V_d=2.5\times 10^{-3} m^3

Mean effective pressure = 6.4 bar

Speed = 2000 rpm

We know that power is the work done per second.

So

P=6.4\times 100\times 2.5\times 10^{-3}\times \dfrac{2\pi \times2000}{120}

We have to notice one point that we divide by 120 instead of 60, because it is a 4 cylinder engine.

P=167.55 KW

So the power developed by engine is 167.55 KW

4 0
3 years ago
Am I alive I really need to know?
Nesterboy [21]
Hell no,cause i’m not
5 0
3 years ago
What does the simplify command do
uranmaximum [27]

Answer:The simplify command is used to apply simplification rules to an expression. The simplify routine searches the expression for function calls, square roots, radicals, and powers and invokes the appropriate simplification procedures. For detailed information on the simplify command, see simplify/details.

Explanation:

4 0
3 years ago
A generator operating at 50 Hz delivers 1 pu power to an infinite bus through a transmission circuit in which resistance is igno
olga55 [171]

Answer:

critical clearing angle = 70.3°

Explanation:

Generator operating at = 50 Hz

power delivered = 1 pu

power transferable when there is a fault = 0.5 pu

power transferable before there is a fault = 2.0 pu

power transferable after fault clearance = 1.5 pu

using equal area criterion to determine the critical clearing angle

Attached is the power angle curve diagram and the remaining part of the solution.

The power angle curve is given as

= Pmax sinβ

therefore :  2sinβo = Pm

                   2sinβo = 1

                   sinβo = 0.5 pu

                   βo = sin^{-1} (0.5) = 30⁰

also ;   1.5sinβ1 = 1

               sinβ1 = 1/1.5

               β1 = sin^{-1} (\frac{1}{1.5} ) = 41.81⁰

∴ βmax = 180 - 41.81  = 138.19⁰

attached is the remaining solution

The critical clearing angle = cos^{-1} 0.3372  ≈ 70.3⁰

3 0
3 years ago
The equation sigma = My/l is used in the mechanics of materials to determine normal stresses in beams. When this equation is exp
Alenkinab [10]

Answer:

Part a : The SI unit of σ is Pascal.

Part b : The pressure is 414.28 psi.

Explanation:

Part a

The equation is given as

\sigma =\frac{My}{l}

As per the dimensional analysis

M=[N-m]\\y=[m]\\l=[m^4]

So the equation becomes

\sigma =\frac{[N-m][m]}{[m^4]}\\\sigma =\frac{[N][m^2]}{[m^4]}\\\sigma =\frac{[N]}{[m^{4-2}]}\\\sigma =\frac{[N]}{[m^{2}]}\\

As the dimensions are of pressure so the SI unit of σ is Pascal.

Part b

\sigma =\frac{My}{l}\\\sigma =\frac{2000 \times 0.1}{7 \times 10^{-5}}\\\sigma =2857142.857  \, Pa

Pressure in US customary base units is given in psi so

1 Pa =1.45 \times 10^{-4}\\

So

\sigma =2857142.857  \times 1.45 \times 10^{-4} psi\\\sigma =414.28 psi

So the pressure is 414.28 psi.

5 0
3 years ago
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