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Vika [28.1K]
2 years ago
6

An NMOS amplifier is to be designed to provide a 0.20-V peak output signal across a 20-kΩ load that can be used as a drain resis

tor.
(a) If a gain of at least 10V/V is needed, what gm is required?
(b) Using a dc supply of 1.8V, what values of ID and VOV would you choose?
(c) What W/L ratio is required if μnCox=200 μA/V^2? If Vt =0.4V, find VGS.

Engineering
1 answer:
sveta [45]2 years ago
6 0

Answer:

Explanation:

All answers have been attached as files please check.

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The pressure difference across hatch of the submarine is 3217.68 kpa.

Explanation:

Gauge pressure is the pressure above the atmospheric pressure. If we consider gauge pressure for finding pressure differential then no need to consider atmospheric pressure as they will cancel out. According to hydrostatic law, pressure varies in the z direction only.  

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Density of sea water is calculated as follows:

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Here, density of sea water is\rho_{sw}, surface gravity is S.G and density of water is \rho_{w}.

Substitute all the values in the above equation as follows:

S.G=\frac{\rho_{sw}}{\rho_{w}}

1.025=\frac{\rho_{sw}}{1000}

\rho_{sw}=1025 kg/m³.

Step2

Difference in pressure is calculated as follows:

\bigtriangleup p=rho_{sw}gh

\bigtriangleup p=1025\times9.81\times320

\bigtriangleup p=3217680 pa.

Or

\bigtriangleup p=(3217680pa)(\frac{1kpa}{100pa})

\bigtriangleup p=3217.68 kpa.

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