Question

1. (02.04 MC)

Answer 1

Answer:

3p⁶ 4s² 3d²

Explanation:

From the question given above,

The electronic configuration of the element ends with 3p².

Another element having 8 more electrons will have the following electronic configuration as illustrated below:

Step 1:

Complete the 3p orbital by adding 4 electrons:

3p² + 4 electrons = 3p⁶

Step 2:

Fill the 4s orbital. This is so because 4s has a lower energy level compared to 3d.

4s²

Step 3:

Fill the 3d orbital with the remaining electrons i.e 2

3d²

Summary:

The continuation of the electronic configuration of the element with 8 more electrons is:

3p⁶ 4s² 3d²