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3 years ago

How is Carbon-12 and Carbon-13 different? What’s is the name that describes these two atoms?

Chemistry

1 answer:

Maslowich3 years ago

4 0

Answer:

Carbon 12 and 13 are carbon isotopes, meaning that they have additional neutrons:

Carbon 12 has exactly 6 protons and 6 neutrons ( hence the 12 )

Carbon 13 has 6 protons and 7 neutrons ( hence the 13 )

They differ in the number of neutrons in the nucleus.

Names:

carbon-13, C-13

carbon-12, C-12

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An aqueous solution is prepared by dissolving 15.6 g of Cu(NO3)2 ⋅ 6 H2O in water and diluting to 345 mL of solution. What is th

Vladimir [108]

<u>Answer:</u> The molarity of $NO_3^-$ ions in the solution is 0.306 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute $(Cu(NO_3)_2.6H_2O)$ = 15.6 g

Molar mass of $(Cu(NO_3)_2.6H_2O)$ = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

$\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M$

As, 1 mole of $(Cu(NO_3)_2.6H_2O)$ produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of $NO_3^-$ ions = (2 × 0.153) = 0.306 M

Hence, the molarity of $NO_3^-$ ions in the solution is 0.306 M

3 0

3 years ago

I WILL GIVE BRAINLIEST

creativ13 [48]

Answer:

i don get it

Explanation:i dont get it

4 0

3 years ago

Which of the following best explains why solids do not

timama [110]

What do you mean by ‘which of the following’? Without that I am not able to answer the question

7 0

3 years ago

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th

MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

$\frac{K_1}{K_2}=?$

Activation energy of the reaction 1 , $Ea_1$ = 14.0 kJ/mol

Activation energy of the reaction 2, $Ea_1$ = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

The expression used with catalyst and without catalyst is,

$\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}$

$\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}$

where,

$K_2$ = rate constant reaction -1

$K_1$ = rate constant reaction -2

Activation energy of the reaction 1 , $Ea_1$ = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2, $Ea_1$ = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = $25^oC=273+25=298 K$

Now put all the given values in this formula, we get

$\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340$

0.4284 is the ratio of the rate constants.

7 0

3 years ago

Non-metallic properties are more pronounced: 1) Si 2) B 3) O 4)S

Ne4ueva [31]

Answer:

1. Si

hope this helped

5 0

3 years ago