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3 years ago

How is Carbon-12 and Carbon-13 different? What’s is the name that describes these two atoms?

Chemistry

1 answer:

Maslowich3 years ago

4 0

Answer:

Carbon 12 and 13 are carbon isotopes, meaning that they have additional neutrons:

Carbon 12 has exactly 6 protons and 6 neutrons ( hence the 12 )

Carbon 13 has 6 protons and 7 neutrons ( hence the 13 )

They differ in the number of neutrons in the nucleus.

Names:

carbon-13, C-13

carbon-12, C-12

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The mass of the ocean is about 1.8 1021 kg. if the ocean contains 1.076% by mass sodium ions, na+, what is the mass in kilograms

castortr0y [4]

In chemistry, if you want to express the amount of a substance out of the total amount, you express it in concentration. There are numerous units of measurement: molarity, molality, normality, mass percentages, volume percentage, or a mix of both. For this problem, the unit used for concentration is in mass percentages. The formula would be

Percentage Concentration = [(Actual Amount of Substance)/(Total amount of all substances)] * 100

Since we are given with the total mass of all the substances in the ocean and the percentage concentration, the only missing information is the actual amount of Na+ in the ocean. Substituting the values:

1.076 = (Amount of Na+ /1.8×10²¹ kg)*100
Amount of Na+ = 1.9368×10¹⁹ kg

5 0

4 years ago

Wet chemical system components typically are a storage tank or tanks, piping, nozzles, and a(an)?

MAVERICK [17]

Wet chemical system components typically are a storage tank or tanks, piping, nozzles, and an actuating mechanism.

<h3>Which parts make up an actuation mechanism?</h3>

The typical components of an actuation mechanism include a motor, transmission, control units, feedback, signaling, interlocking, and shutdown units. An electrical, hydraulic, or pneumatic drive is used to move a valve, shutter, or gate, which acts as an actuator to regulate the flow of fluids or gases.

<h3>What is the operation of the operator-dependent actuating mechanism?</h3>

When an automatic clutch is engaged, the control system 2 replaces the target-value signals coming over feeders 1 with the operator force signal if the operator uses the operator-dependent actuating mechanism.

Learn more about automatic clutch here:-

brainly.com/question/8012302

#SPJ4

5 0

2 years ago

A person accidentally swallows a drop of liquid oxygen, O2(l), which has a density of 1.149 g/mL. Assuming the drop has a volume

nasty-shy [4]

Answer:

First, let's determine how many moles of oxygen we have.

Atomic weight oxygen = 15.999

Molar mass O2 = 2*15.999 = 31.998 g/mol

We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml

Since the density is 1.149 g/mol,

we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2

Divide the number of grams by the molar mass to get the number of moles 0.17235 g / 31.998 g/mol = 0.005386274 mol

Now we can use the ideal gas law. The equation PV = nRT where P = pressure (1.0 atm) V = volume n = number of moles (0.005386274 mol) R = ideal gas constant (0.082057338 L*atm/(K*mol) ) T = Absolute temperature ( 30 + 273.15 = 303.15 K)

Now take the formula and solve for V, then substitute the known values and solve.

PV = nRT V = nRT/P V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm V = 0.133987239 L*atm / 1.0 atm V = 0.133987239 L

So the volume (rounded to 3 significant figures) will be 134 ml.

8 0

3 years ago

Read 2 more answers

What is the molar solubility of MgF2 in a 0.36 M Mg(NO3)2 solution? For MgF2, Ksp = 8.4 × 10^–8

Valentin [98]

Answer:

2.4 × 10⁻⁴ M

Explanation:

Step 1: Calculate the concentration of Mg²⁺ coming from Mg(NO₃)₂

Mg(NO₃)₂ is a strong electrolyte and the molar ratio of Mg(NO₃)₂ to Mg²⁺ is 1:1. The initial molar concentration of Mg²⁺ is 1/1 × 0.36 M = 0.36 M.

Step 2: Make an ICE chart for the solution of MgF₂

MgF₂(s) ⇄ Mg²⁺(aq) + 2 F⁻(aq)

I 0.36 0

C +S +2S

E 0.36+S 2S

The solubility product constant is:

Ksp = [Mg²⁺] × [F⁻]² = (0.36+S) × (2S)²

Since S <<< 0.36, 0.36+S ≈ 0.36.

Ksp = 0.36 × 4S² = 8.4 × 10⁻⁸

S = 2.4 × 10⁻⁴ M

7 0

3 years ago

What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin

Contact [7]

<u>Answer:</u> The total volume of the gaseous products is 1044.29 L

<u>Explanation:</u>

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = $\frac{1}{22.4}\times 116=5.18mol$ of butane

The chemical equation for the combustion of butane follows:

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

<u>For carbon dioxide:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = $\frac{8}{2}\times 5.18=20.72mol$ of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

<u>For water vapor:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = $\frac{10}{2}\times 5.18=25.9mol$ of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0

3 years ago