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tamaranim1 [39]
3 years ago
7

Which tool or tools would you use to measure and compare the mass of a cup of fresh water and a cup of salt water

Chemistry
1 answer:
Artemon [7]3 years ago
4 0
You could use a scale to measure the mass as well as a cup to hold the water. If you were comparing the two, you should also probably use a graduated cylinder to get the same amount of each type of water.

Hope this helped ^_^
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2. Find the two generic molecules from Part 1 that are made of 3 atoms. a. Compare and contrast these two molecules by listing t
Stells [14]

Answer:

hello the molecules are missing from your question below are the Generic molecules : ABE_{3} and AB_{3} E

answer : It can be determined  that both generic molecules are polar

It can be determined that both generic molecules have similar molecular shape

They have different Geometry

They differ in bond angles as well

Explanation:

The two generic molecules : ABE_{3} and AB_{3} E

comparing(similarities) these two generic molecules

It can be determined  that both generic molecules are polar

It can be determined that both generic molecules have similar molecular shape

differences between the generic molecules

They have different Geometry

They differ in bond angles as well

3 0
3 years ago
If you started with 35.0 grams of H2S and 40.0 grams of O2, how many grams of S8 would be produced, assuming 95 % yield? 8H2S(g)
Vesnalui [34]
Molar mass

H2S = 34.0 g/mol
O2 = 31.99 g/mol
S8 = 256.52 g/mol

Identifying excess reagent and the limiting of the reaction :

8 H2S(g) + 4 O2(g) = S8(I) +  8 H2O(g)

8 x 34 g H2S -------->  256. 52 g S8
35.0 g ----------------> ??

35.0 x 256.52 / 8 x 34 =

8978.2 / 272 => 33.00 g of S8  

H2S is  the  limiting reactant
---------------------------------------------

4 x 31.99 g O2 --------------- 256.52 g S8
40.0 g O2 --------------------- ??

40.0 x 256.52 / 4 x 31.99 =

10260.8 / 127.96 = 80.16 g of S8  

O2 is the excess reagent is the excess <span>reagent
</span>
------------------------------------------------------------

H2S is the limiting reactant, one that is fully consumed, it is he who determines the mass of S8 produced 

33.0 g ----------- 100%
?? g ------------- 95 %

95 x 33.00 / 100 => 31.35 g

hope this helps!


4 0
3 years ago
Calculate how many moles of element Q are in 23.53 g of element Q.
pogonyaev

Answer:

0.579 moles

Explanation:

Moles = 23.53/40.64

= 0.5789 moles

7 0
3 years ago
PLEASE HELP ME WILL DO ANYTHING ‼️‼️
deff fn [24]

Answer:

In first shell 2 electrons are present and 7 electrons are present in last shell

Explanation:

6 0
3 years ago
What's is the mass of 0.500 mol NH3​
Setler [38]

Answer:

8.5155g NH3

Explanation:

the molar mass of NH3​ is 17.031 g/mol

0.5 mol NH3 x 17.031 gNH3/1 mol NH3 = 8.5155g NH3

4 0
3 years ago
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