1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
Answer:
x = 5
Step-by-step explanation:
a || b and a line intersecting them is their transversal.
Answer:
(8,3)
Step-by-step explanation:
Point c is seven units away from the line x = 1
So we move seven units to the right of the line x = 1
the x value = 8
y value = 3
Coordinates = (8,3)
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-Chetan K
Answer:
For inch/min =0.9167 inch/min
For min/inch = 1.0908 min/inch
Step-by-step explanation:
The snail in the race traveled 11/6 inches in 2 minutes.
The number of inches per minute is equal to = (11/6)/(2)
= 11/12
=0.9167 inch/min
The number of minutes per inch is equal to = 1/(inch per min)
= 1/0.9167
= 1.0908 min/inch
Minutes per inch is gotten by taking the inverse of inch/min or dividing the number of minutes by number of inches
