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lesya692 [45]
3 years ago
12

Write the balanced nuclear equation for alpha decay of polonium−218. include both the mass numbers and the atomic numbers with e

ach nuclear symbol. use the "sup-subscript" button in the answer palette to enter these numbers correctly. greek letters can be accessed in the drop-down menu that says "-select−."
Chemistry
1 answer:
Dvinal [7]3 years ago
7 0
<span>Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.
Nuclear reaction: </span>₈₄²¹⁸Po → ₈₂²¹⁴Pb + α (alpha particle).<span>
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.</span>
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A gas sample has a temperature of 19 °C with an unknown volume. The
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Answer: 373 mL

Explanation:

Since there is no change in pressure, the formula: V / T = V / T can be used.

However, you must first convert the temperatures to Kelvin by adding 273 to them:

(19 + 273) = 292K and (90 + 273) = 363K.

Now, plug in: V / 292 = 464 / 363 → V = 373 mL :)

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3 years ago
What is the volume of a sample of ammonia gas (NH3) if it contains 0.23 moles?​
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The volume of a sample of ammonia gas : 5.152 L

<h3>Further explanation</h3>

Given

0.23 moles of ammonia

Required

The volume of a sample

Solution

Assumed on STP

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So for 0.23 moles :

= 0.23 x 22.4 L

= 5.152 L

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A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to
12345 [234]

Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

\frac{salt}{sugar}  = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}

Now we can calculate the amount of sugar in the final solution:

\frac{salt}{sugar}  = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g

Finally, we calculate the amount of water:

\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g

4 0
3 years ago
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