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Juli2301 [7.4K]
3 years ago
7

_______________________ turns blood to cherry red and produces a patchy, pinkish color in the lividity of the corpse.a. Carbon m

onoxideb. Carbon dioxidec. Carbon d. None of these
Chemistry
1 answer:
IgorC [24]3 years ago
8 0

Answer: a. Carbon monoxide

Explanation:

The carbon monoxide gas competes with the oxygen in the blood to occupy the binding affinity of the hemoglobin thus the blood changes it's color to cherry red.

In postmortem lividity, the body becomes discolored due to the effect of flow of blood from the interstitial tissues and suspended under the force of gravity. This can be seen on the dependent parts of the body and the position of body after death. The color of the postmortem lividity depends on the color of the hemoglobin.

In case of carbon monoxide poisoning the color of postmortem lividity appears to be cherry red as color of the hemoglobin is cherry red. Thus cherry red or dark pinkish patches appear in the corpse as lividity.

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If there is no subscript to the right of a symbol means ________________ atom of that element?
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What effect does adding a neutron have on the atoms identity
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The half-life of radon-222 is 3.8 days. If a sample currently contains 3.1 grams of radon-222, how much radon-222 did this sampl
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 <u>calculation</u>

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             that is  divide 15.2/ 3.8 = 4 half life

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5 0
3 years ago
• 1) The pressure of a sample of gas in a 2.00-L container is 876 mmHg.
kifflom [539]

Answer:

4380 mmHg

Explanation:

Boyle's Law can be used to explain the relationship between pressure and volume of an ideal gas. The pressure is inversely related to volume, so if volume decrease the pressure will increase. It can be expressed in the equation as:

P1V1=P2V2

In this question, the first condition is 2L volume and 876 mmHg pressure. Then the system changed into the second condition where the volume is 400ml and the pressure is unknown. The pressure will be:

P1V1= P2V2

876 mmHg * 2L = P2 * 400ml /(1000ml/L)

P2= 876 mmHg * 2L / 0.4L

P2= 4380 mmHg

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3 years ago
How many “p” orbital in principal energy level below?​
marshall27 [118]

Answer:

Each principal energy level above the first contains one s orbital and three p orbitals. A set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. Therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

Explanation:

5 0
3 years ago
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