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Juli2301 [7.4K]
3 years ago
7

_______________________ turns blood to cherry red and produces a patchy, pinkish color in the lividity of the corpse.a. Carbon m

onoxideb. Carbon dioxidec. Carbon d. None of these
Chemistry
1 answer:
IgorC [24]3 years ago
8 0

Answer: a. Carbon monoxide

Explanation:

The carbon monoxide gas competes with the oxygen in the blood to occupy the binding affinity of the hemoglobin thus the blood changes it's color to cherry red.

In postmortem lividity, the body becomes discolored due to the effect of flow of blood from the interstitial tissues and suspended under the force of gravity. This can be seen on the dependent parts of the body and the position of body after death. The color of the postmortem lividity depends on the color of the hemoglobin.

In case of carbon monoxide poisoning the color of postmortem lividity appears to be cherry red as color of the hemoglobin is cherry red. Thus cherry red or dark pinkish patches appear in the corpse as lividity.

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The smallest unit which maintains the physical properties of a compound is a(n) _____.
Luden [163]
Molecule
The smallest unit in a compound is its molecule.
8 0
3 years ago
Explain the difference between fixed and variable oxidation
dem82 [27]

Fixed vs Variable Oxidation is given below.

Explanation:

1.In its compounds, hydrogen has an oxidation number of +1, except. hydrides where the. oxidation number of hydrogen is -1. In their compounds, the metals with fixed oxidation states have the oxidation number that. corresponds with the fixed oxidation number.

A variable oxidation state is a value that determines the charge of the atom depending on certain conditions.

2. Ox­i­da­tion state of el­e­ments is con­sid­ered to be of the most im­por­tant in the study of chem­istry. For some el­e­ments, this fig­ure is con­stant known as fixed oxidation , while for oth­ers it is vari­able is called variable oxidation state.

3. MgCl2 :  magnesium is in Group IIA and all elements in Group IIA have fixed oxidation numbers of +2

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7 0
3 years ago
Consider the cell pt | h2 (1 atm); h+ (? m) || hg2cl2(s); cl− (1 m) | hg 2 h+ + 2 e − → h2 e 0 = 0.00 v hg2cl2 + 2 e − → 2 hg +
Dmitry [639]

Answer:

1.39

Explanation:

[Hg2Cl2]= 1M

[H^+] = ????

E°cell= 0.35V

E= 0.268 V

Therefore E for the reaction must -0.082 V

n= 2 moles of electrons

From Nernst Equation:

E= E°cell- 0.0592/n log [Red]/[Ox]

0.0268= 0.35- 0.0592/2 log 1/[Ox]^2

-0.082= -0.0296 log 1/[Ox]^2

log 1/[Ox]^2= 0.082/0.0296

log 1/[Ox]^2= 2.77

1/[Ox]^2=Antilog (2.77)

[Ox]^2=1.698×10^-3

[Ox] = 0.0412 M

But pH= -log [H^+]= -log(0.0412)= 1.385

3 0
3 years ago
Read 2 more answers
Give the spectator ions for the reaction that occurs when aqueous solutions of H 2SO 4 and KOH are mixed.
Sever21 [200]

Answer:

The spectator ions is: K^+   and  SO^{2-}_4

Explanation:

The equation of reaction between  H₂ SO₄ and KOH is:

H_2SO_{4(aq)} + 2KOH _{aq} \to K_2SO_{4(aq)} +2H_2O _{(l)}

Rewriting this equation as ionic;

[2H^{+} + SO^{2-}_4 + 2K^+ +2OH^- \to 2K^+  SO_4^{2-} + 2H_2O ]

Spectators ions are ions present on both sides of the ionic equation by the same quantity but do not take part in the net reaction.

5 0
3 years ago
Calculate the number of moles in the following: 2.8 X 10^24 atoms of Cl2
vova2212 [387]

Answer:

<h3>The answer is 4.65 moles</h3>

Explanation:

To find the number of moles given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

n =  \frac{2.8 \times  {10}^{24} }{6.02 \times  {10}^{23}  }  \\  = 4.65116279069...

We have the final answer as

<h3>4.65 moles</h3>

Hope this helps you

7 0
3 years ago
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