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Likurg_2 [28]
2 years ago
6

Find the length of side x in simplest radical form with a rational denominator.

Mathematics
2 answers:
olga_2 [115]2 years ago
6 0

Answer:

10

Step-by-step explanation:

\sin 30\degree = \frac{5}{x}\\\\ \frac{1}{2}= \frac{5}{x}\\\\x = 5\times 2\\\\x = 10 \\

hram777 [196]2 years ago
5 0

Officer: "How old was she?!"

Seggs Defender: ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

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Answer:

A' (11, 4), B' (-10, -6), C' (7, -9)

Step-by-step explanation:

Since you are reflecting over the y-axis, you take the opposite of the x value. So if the x is positive, make it negative. If the x is negative, make it positive. The y coordinate stays the same.

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A plumber charges $25 for a service call plus $50 per hour for service. Write a linear equation in slope-intercept form to repre
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Answer:

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Step-by-step explanation:

Slope-intercept form is y=mx+b

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A hotel offers a reward program based on the number of night stayed. The function f(x) represents the number of free nights earn
iris [78.8K]

Answer:

a. A customer earns 1 free night per 10 nights stayed.  

Step-by-step explanation:

The missing function is:

f(x) = x/10  

The missing options are:

<em> a. A customer earns 1 free night per 10 nights stayed.  </em>

<em> b. A customer starts with 1 free night and then earns another free night after every 10 nights stayed. </em>

<em> c.A customer earns x – 10 free nights for every 10 nights stayed.  </em>

<em> d. A customer earns 10 free nights after x number of nights stayed. </em>

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7 0
3 years ago
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Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
2 years ago
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