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babymother [125]
3 years ago
9

Which statement is true about a neutral solution? Its pH is less than 7. Its pH is greater than 7. It has the same concentration

of hydronium and hydroxide ions. It has a greater concentration of hydroxide ion than hydronium ions.
Chemistry
2 answers:
kumpel [21]3 years ago
7 0

Answer:

Option C It has the same concentration of hydronium and hydroxide ions is correct.

Explanation:

A neutral solution will have pH=7

and the concentration of hydronium ions and hydroixde ions is the same.

So, Option C It has the same concentration of hydronium and hydroxide ions

is correct.

katrin [286]3 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

A solution whose pH is less than 7 is known as an acidic solution. In this solution, concentration of hydrogen ions is more than hydroxide ions.

Whereas a solution whose pH is more than 7 is known as a basic solution. In this solution, concentration of hydroxide ions is more than hydrogen ions.

On the other hand, when pH of a solution is equal to 7 then the solution will be known as neutral solution. That is, the concentration of both hydrogen and hydroxide ions is same in a neutral solution.

Thus, we can conclude that the statement it has the same concentration of hydronium and hydroxide ions, is true about a neutral solution.

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What volume (ml) of fluorine gas is required to react with 1. 28 g of calcium bromide to form calcium fluoride and bromine gas a
Alexandra [31]

144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

<h3>What is Ideal Gas Law ? </h3>

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

PV = nRT

where,

P = Presure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = temperature in Kelvin

Here,

P = 1 atm  [At STP]

R = 0.0821 atm.L/mol.K

T = 273 K  [At STP]

Now first find the number of moles

F₂  +  CaBr₂  →  CaF₂  +  Br₂

Here 1 mole of F₂ reacts with 1 mole of CaBr₂.

So,  199.89 g CaBr₂ reacts with  = 1 mole of F₂

1.28 g of CaBr₂ will react with = n mole of F₂

n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}

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Now put the value in above equation we get

PV = nRT

1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K

V = 0.1434 L

V ≈ 144 mL

Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

Learn more about the Ideal Gas here: brainly.com/question/20348074

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