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2 years ago

15

What is the speed u of the object at the height of (1/2)hmax? Express your answer in terms of v and g. Use three significant fig

ures in the numeric coefficient.

1 answer:

max2010maxim [7]2 years ago

3 0

The speed u of the object at the height of (1/2) hmax is $0.707$ $v_{i}$ .

<u>Explanation:</u>

At a height that is half of the maximum height, the object will have only half of its initial kinetic energy, the rest half is converted to potential energy at this point. So,

$1 / 2 m v^{2} _{i} = m (v_{mid})^{2} }$

$v_{mid} = \frac{v}{\sqrt{2} }$

$v_{mid} =$ $0.707$ $v_{i}$ .

The speed u of the object at the height of (1/2) hmax is $0.707$ $v_{i}$ .

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Explanation:

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2 years ago

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Answer:

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