20 J of energy was used to
1 answer:
Answer:
0.3m
Explanation:
Given parameters;
Elastic energy = 20J
Spring constant = 445N/m
Unknown
Final extension of the spring = ?
Solution:
The elastic potential energy of a stretched spring can be determined using the expression below;
EP = k e²
k is the spring constant
e is the extension
Insert the parameters and solve;
20 = x 445 x e²
multiply those sides by 2;
2(20) = 445e²
40 = 445e²
e² = = 0.09
e = √0.09 = 0.3m
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Answer:
F = 1,875 N
Explanation:
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∆H = m∆V
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