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STatiana [176]
3 years ago
9

A gas occupies 12.5 ft at - 173 °C. At what Celsius temperature will its volume be 16.0

Chemistry
1 answer:
Elza [17]3 years ago
8 0

Answer:

T₂ = 128.19 K

Explanation:

Given that,

The initial volume, V₁ = 12.5 ft³

Initial temperature, T₁ = -173 °C = 100.15 K

Final volume, V₂ = 16 ft³

We need to find the new temperature. The relation between temperature and volume is given by :

V\propto T\\\\\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}

Put all the values,

T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{100.15\times 16}{12.5}\\\\T_2=128.19\ K

So, the new temperature is 128.19 K.

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If 13.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
Paul [167]

6.349 g mass of anhydrous magnesium sulfate will remain.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 1023 of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass MgSO₄.7 H₂O = 246.52 g/mol

Moles =\frac{mass}{molar \;mass}

Moles =\frac{13.0 g}{246.52}

0.0527 moles

Molar mass MgSO₄ = 120.4 g/mol

Mass of anhydrous magnesium sulfate :

( 0.0527 x 120.4 ) => 6.349 g

Learn more about moles here:

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2 years ago
Which of the following is not a type of mechanical wave?
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Concave is not a type of mechanical wave because it doesn’t need a medium for propagation.
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Explain the difference between molecule and compound
nadya68 [22]
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A molecule is a group of two or more atoms held together by chemical bonds. A compound is a substance which is formed by two or more different types of elements which are united chemically in a fixed proportion. All molecules are not compounds.

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How many moles of potassium nitrate, KNO3 are present in a sample with a mass of 85.2 g?
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RideAnS [48]

Answer:

Option C

CH₃CH₂CH₂COOH

Explanation:

Carbonxylic acids are compounds which has the general formula

R–COOH where R is an alkyl group.

Considering the options given in the question above,

For A:

CH₃CH₂OCH₂CH₃ is an ether compound with general formula ROR' where R and R' are both alkyl group.

For B:

CH₃CH₂CH₂CH₂OH is an alcohol with general formula ROH where R is an alkyl group.

For C:

CH₃CH₂CH₂COOH is a carbonxylic acid with general formula R–COOH where R is an alkyl group.

For D:

CH₃CH₂C=OCH₂CH₃ is a ketone compound with general formula RC=OR' where R and R' are both alkyl group

For E:

ClCH₂CH₂CH₂CH₂CH₂CH₂Br is simply an Alkyl halide with general formula XRX where X is an halogen (i.e F, Cl, Br or I) and R is an alkyl group.

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8 0
3 years ago
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