Question

A gas occupies 12.5 ft at - 173 °C. At what Celsius temperature will its volume be 16.0

Answer 1

Answer:

T₂ = 128.19 K

Explanation:

Given that,

The initial volume, V₁ = 12.5 ft³

Initial temperature, T₁ = -173 °C = 100.15 K

Final volume, V₂ = 16 ft³

We need to find the new temperature. The relation between temperature and volume is given by :

$V\propto T\\\\\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

Put all the values,

$T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{100.15\times 16}{12.5}\\\\T_2=128.19\ K$

So, the new temperature is 128.19 K.