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vova2212 [387]
3 years ago
6

Calculate the Ka of a 0.35M weak acid with a pH of 4.2.

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
8 0

Answer:

Ka = 1.14x10⁻⁸

Explanation:

First we <u>calculate [H⁺] from the pH</u>:

  • pH = -log[H⁺]
  • [H⁺] = 10^{-pH}
  • [H⁺] = 6.31x10⁻⁵ M

For a monoprotic weak acid, the molar concentration of H⁺ of a solution can be expressed as:

  • [H⁺] = √(C*Ka)

Where C is the molar concentration of the weak acid solution.

  • 6.31x10⁻⁵ M = \sqrt{0.35M*Ka}
  • 1.14x10⁻⁸ = Ka
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