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Dmitriy789 [7]
3 years ago
8

A 2-column table with 5 rows. The first column titled metal has entries aluminum, cork, iron, lead, wax. The second column title

d Density (grams per cubic centimeter) has entries 2.64, 0.24, 7.50, 11.34, 0.72. If the density of water is 1.0 g/cm3, which of these materials would float in water, based on their densities? Check all that apply. aluminum cork iron lead wax
Physics
2 answers:
astraxan [27]3 years ago
9 0

Answer:Cork and wax

Explanation:

ruslelena [56]3 years ago
8 1

Answer: Iron

Explanation:

I did it on edge 2020 and got it correct tytyty

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Solving this using the time, we know that range = horizontal velocity x time of flight 

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3 years ago
a 1200 kg car rolling on a horizontal surfact has a speed of 25 m/s when it strikes a horizontal coiled spring and is brought ot
gizmo_the_mogwai [7]

The required spring constant:

The spring constant of the spring is 12\times 10^4 \text{ N/m}.

Calculation:

The mass of the car is m=1200 kg, the speed of the car is v=25 m/s, and after colliding the spring is brought to rest at a distance of x=2.5m. Let the spring constant of the spring is, k.

From the conservation of energy,

Total initial kinetic energy= Total final potential energy of the spring

Therefore,

\frac{1}{2}mv^2=\frac{1}{2}kx^2

Now, substituting the values of the mass of the car, speed of the car, and displacement, we get:

$$\begin{aligned}1200\times(25)^2&=k\times (2.5)^2\\\Rightarrow k&=\frac{1200\times(25)^2}{(2.5)^2}\\&=12\times 10^4 \text{ N/m}\end{aligned}$$

To know more about spring constant, refer to:

brainly.com/question/14159361

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5 0
2 years ago
When an object threw to the free space to make an angle of 25 degree at an initial speed of 15 m/sec, the ball takes time to rea
alekssr [168]

Answer:

The horizontal distance traveled by the projectile is 15.23 m.

Explanation:

Given;

angle of projection, θ = 25⁰

initial velocity of the projectile, u = 15 m/s

time of flight, t = 1.12 s

The the travelling path of the object is calculated as the range of the projectile

R = u_x t\\\\R = (15\ Cos \ 25^0) \times 1.12\\\\R = 13.595 \times 1.12\\\\R = 15.23 \ m

Therefore, the horizontal distance traveled by the projectile is 15.23 m.

8 0
3 years ago
Answers for these 2 please
Sholpan [36]
I think the answer for question 1 is 4.
4 0
3 years ago
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