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Dmitriy789 [7]
3 years ago
8

A 2-column table with 5 rows. The first column titled metal has entries aluminum, cork, iron, lead, wax. The second column title

d Density (grams per cubic centimeter) has entries 2.64, 0.24, 7.50, 11.34, 0.72. If the density of water is 1.0 g/cm3, which of these materials would float in water, based on their densities? Check all that apply. aluminum cork iron lead wax
Physics
2 answers:
astraxan [27]3 years ago
9 0

Answer:Cork and wax

Explanation:

ruslelena [56]3 years ago
8 1

Answer: Iron

Explanation:

I did it on edge 2020 and got it correct tytyty

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Object A has a mass of 5 kg and a velocity of 6 m/s to the east while Object 1 point B has a mass of 12 kg and velocity 0.6 m/s
Olin [163]

Answer:

Momentum of system = 37.2 Kgm/s.

Explanation:

<u>Given the following data;</u>

  • Mass A = 5 kg
  • Velocity A = 6 m/s
  • Mass B = 12 kg
  • Velocity B = 0.6 m/s

To find the momentum of the system;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

<u>For object A;</u>

Momentum A = 5 * 6

Momentum A = 30 Kgm/s

<u>For object B;</u>

Momentum B = 12 * 0.6

Momentum B = 7.2 Kgm/s

Next, we would determine the momentum of this system using the formula;

Momentum of system = Momentum A + Momentum B

Substituting the values into the formula, we have;

Momentum of system = 30 + 7.2

<em>Momentum of system = 37.2 Kgm/s.</em>

8 0
2 years ago
tyhe mass of an object is 117 g adding 1200j of heat will raise the temperture of the object by 12 celsius what is the specifc h
Sati [7]

Answer:

C 0.85 j/g*k

Explanation:

The specific heat capacity of a material is given by:

C_s = \frac{Q}{m \Delta T}

where

Q is the amount of heat supplied to the object

m is the mass of the object

\Delta T is the increase in temperature of the object

For the object in this problem, we have

m = 117 g is the mass

Q = 1200 J is the heat supplied

\Delta T=12^{\circ} is the increase in temperature

Substituting into the formula, we find the specific heat:

C_s = \frac{1200 J}{(117 g)(12^{\circ})}=0.85 J/gC

8 0
3 years ago
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Form of mechanical energy
never [62]

Answer:

Explanation:

Potential energy and kinetic energy

4 0
2 years ago
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